Is there a way to set setContentView(int id) dynamically?

问题

I'd like to be able to loop through a list of xml layout files instead of having to specify a particular one in the setContentView argument.

Obviously the types are incorrect, but something like:

ArrayList<String> pages = new ArrayList<String>();
//(Where each of the xml pages are stored like R.layout.page1, R.layout.page2, etc)
setContentView(pages.get(0));

Is this possible somehow?

回答1:

You should use the ViewFlipper widget instead. Here is an example.

It is cleaner to manage the content views and their children widgets this way.

Anyway, the resource IDs can be obtained from names using the Resources.getIdentifier method.

回答2:

Yes. it's possible. But two notes:

1. The ids are ints, not Strings.
2. You need to manage the views inside them properly.

回答3:

In an application I have created I use the following code to set the image button to a particular resource:

imgBtnCard.setImageResource(this.getResources()
    .getIdentifier("com.twp.cptshitface:drawable/" +
        cardType + cardDetails[1] , null, null));

I would say that this is what you are looking for:

int resLayoutId = this.getResources().
    getIdentifier("your.package.namespace:layout/" +
    pages.get(0), null, null);

setContentView(resLayoutId);
// where pages.get(0) returns a string such as "main2"

I've quickly tested this code in the onCreateMethod.

remember to clean your project if you add more layouts and/or resources so the id's are updated!

来源：https://stackoverflow.com/questions/8248861/is-there-a-way-to-set-setcontentviewint-id-dynamically