问题
How would the regexp_extract change if this data was in a column named "pages" and I want for every row that has ':old:yes:' to return the string after 'yes:' and before the next string?
PAGES (table name)
hello:ok:old:yes:age:test:jack
hello:no:old:yes:hour:black:nancy
hi:fine:old:yes:minute:white:jason
As you can see ':old:yes:' is my starting point and i want the regexp_extract to return the next text before the colon. In the above example I would want the following results:
age
hour
minute
回答1:
select regexp_extract(page,':old:yes:([^:]+)',1)
from pages
where page like '%:old:yes:%'
+--------+
| age |
| hour |
| minute |
+--------+
来源：https://stackoverflow.com/questions/42863025/extract-data-from-a-string-sql