问题
NOT A DUPLICATE OF THIS: This has been flagged as a duplicate of the link that I added to an existing StackOverflow Question and Solution. This is not a duplicate as that question specifically deals with XmlElements. I am looking for a way to mould that solution to work with XmlAttributes as well as XmlElements.
I am building a Class Library that interacts with Web Service that returns XML. This Web Service is attached to a Document Management System. I have built an object for each type of entity that is in the system (Folder, Document, User, etc.). I currently have an issue where there are three different operations that return a list of documents that are in a specified directory. Each operation returns the document metadata in a different format.
<d id="1104" name="Intro.pdf" cdate="2018-06-08 13:27:05" size="188481" />
<d id="1104" n="Intro.pdf" s="188481" />
<document DocumentID="1104" Name="Intro.pdf" CreationDate="2018-06-08 13:27:05" Size="188481" />
All of these elements are for the exact same document. I am wanting to deserialise each of these into the same object called Document rather than return a different type for each item.
I found a great solution here for working with synonyms for elements. The only problem is that it does not show how I could add synonyms in for Attributes.
I have attempted to create another method that is called for the UnknownAttribute event but I have not been successful. The method is just a copy of the SynonymHandler method in the previous link, but I have altered it slightly.
protected void AttributeSynonymHandler(object sender, XmlAttributeEventArgs e)
{
//this part works as it returns the correct property to me
var member = SynonymsAttribute.GetMember(e.ObjectBeingDeserialized, e.Attr.Name);
Type memberType;
if (member != null && member is FieldInfo)
memberType = ((FieldInfo)member).FieldType;
else if (member != null && member is PropertyInfo)
memberType = ((PropertyInfo)member).PropertyType;
else
return;
if (member != null)
{
//this is where the logic falls down, mainly because I don't have the original element anymore.
object value;
XmlSynonymDeserializer serializer = new XmlSynonymDeserializer(memberType, new XmlRootAttribute(e.Attr.Name));
using (System.IO.StringReader reader = new System.IO.StringReader(e.Attr.OuterXml))
value = serializer.Deserialize(reader);
if (member is FieldInfo)
((FieldInfo)member).SetValue(e.ObjectBeingDeserialized, value);
else if (member is PropertyInfo)
((PropertyInfo)member).SetValue(e.ObjectBeingDeserialized, value);
}
}
I am probably going about it wrong, but I was really hoping that I would be able to avoid manually handling the attributes in each case. Any help is appreciated.
EDIT: I also have the same issue when it comes to other types (e.g. Folders) so I am looking for a single solution rather than having to create a separate deserialiser for each object that this happens to. That is why I really liked the SynonymAttribute : Attribute solution. It kept all the important information together and used Reflection to find which Attribute I was looking for.
回答1:
Using xml linq you can use following code :
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication48
{
class Program
{
const string FILENAME = @"c:\temp\test.xml";
static void Main(string[] args)
{
XDocument doc = XDocument.Load(FILENAME);
var groups = (from d in doc.Descendants("d")
join xdoc in doc.Descendants("document") on (string)d.Attribute("id") equals (string)xdoc.Attribute("DocumentID")
select new List<XElement> { d, xdoc })
.GroupBy(x => (string)x.FirstOrDefault().Attribute("id"))
.Select(x => x.SelectMany(y => y).ToList())
.ToList();
List<Document> documents = new List<Document>();
foreach (var group in groups)
{
Document newDoc = new Document();
documents.Add(newDoc);
foreach (XElement element in group)
{
foreach (XAttribute attribute in element.Attributes())
{
switch (attribute.Name.LocalName.ToUpper())
{
case "ID" :
newDoc.id = (string)attribute;
break;
case "DOCUMENTID":
newDoc.id = (string)attribute;
break;
case "NAME":
newDoc.name = (string)attribute;
break;
case "N":
newDoc.name = (string)attribute;
break;
case "CDATE":
newDoc.date = (DateTime)attribute;
break;
case "CREATIONDATE":
newDoc.date = (DateTime)attribute;
break;
case "SIZE":
newDoc.size = (long)attribute;
break;
case "S":
newDoc.size = (long)attribute;
break;
default :
break;
}
}
}
}
}
}
public class Document
{
public string id { get; set; }
public string name {get; set; }
public long size { get; set; }
public DateTime date { get; set; }
}
}
来源：https://stackoverflow.com/questions/50792632/multiple-names-for-xml-elements-and-attributes