问题
I hava a df,
A B
one six
two seven
three level
five one
and a dictioinary
my_dict={1:"one,two",2:"three,four"}
I want to replace df.A with my_dict keys()
my desired output is,
A B
1 six
1 seven
2 level
five one
I tried df.A.replace(my_dict,regex=True)
but goes wrong
pls help, thanks in advance!
回答1:
You need dict comprehension for separate each values to keys first:
my_dict={1:"one,two",2:"three,four"}
d = {k: oldk for oldk, oldv in my_dict.items() for k in oldv.split(',')}
print (d)
{'one': 1, 'three': 2, 'four': 2, 'two': 1}
df.A = df.A.replace(my_dict)
回答2:
Here is one solution via map
/ fillna
:
d = {v_i: k for k, v in my_dict.items() for v_i in v.split(',')}
df['A'] = df['A'].map(d).fillna(df['A'])
# A B
# 0 1 six
# 1 1 seven
# 2 2 level
# 3 five one
来源:https://stackoverflow.com/questions/49008179/how-to-replace-column-values-with-dictionary-keys-in-pandas