Floating point Endianness?

Question

I'm writing a client and a server for a realtime offshore simulator, and, as I have to send a lot of data through a socket, I'm using binary data to maximize the ammount of data I can send. I already know about integers endianness, and how to use htonl and ntohl to circumvent endianness issues, but my application, as almost all simulation software, deals with a lot of floats.

My question is: Is there some issue of endianness whean dealing with binary formats of floating point numbers? I know that all the machines where my code will run use IEEE implementation of floating points, but is there some endianness issue when dealing with floats?

Since I only have access to machines with the same endian, I cannot test this by myself. So, I'll be glad if someone can help me with this.

Thanks in advance.

Answer 1

Yes, floating point can be endianess dependent. See Converting float values from big endian to little endian for info, be sure to read the comments.

Answer 2

According to Wikipedia,

Floating-point and endianness

On some machines, while integers were represented in little-endian form, floating point numbers were represented in big-endian form. Because there are many floating point formats, and a lack of a standard "network" representation, no standard for transferring floating point values has been made. This means that floating point data written on one machine may not be readable on another, and this is the case even if both use IEEE 754 floating point arithmetic since the endianness of the memory representation is not part of the IEEE specification.

Answer 3

EDIT: THE FOLLOWING IS WRONG ANSWER (leaving so that people know that this 'somewhat popular' view is wrong, please read the accepted answer and comments on this answer)

--WRONG ANSWER BEGIN--

There is no such thing as floating point endianness or integer endianness etc. Its just binary representation endianness. Either a machine is little-endian, or its big-endian. Which means that it will either represent the MSb/MSB in the binary representation of any datatype as its first bit/byte or last bit/byte. Thats it.

--WRONG ANSWER END---