问题
This is what I have in a public method - (IBAction)methodName
NSString *quoteNumber = [[self textBox] text];
NSURL *url = [[NSURL alloc] initWithString:@"http://TestSite.com/virdirectory/Webservice1/Service1.asmx/GetQuote?number=%d", quoteNumber];
The error I get is:
Too many arguments to method call, expected 1, have 2
What am I doing wrong?
回答1:
The initWithString method can only accept a normal NSString, you are passing it a formatted NSString, Take a look at this code:
NSURL *url = [[NSURL alloc] initWithString:[NSString stringWithFormat:@"http://TestSite.com/virdirectory/Webservice1/Service1.asmx/GetQuote?number=%d", quotedNumber]];
That might be a bit confusing, you can break it up as follows:
NSString *urlString = [NSString stringWithFormat:@"http://TestSite.com/virdirectory/Webservice1/Service1.asmx/GetQuote?number=%d", quotedNumber];
NSURL *url = [[NSURL alloc] initWithString:urlString];
Now your string is properly formated, and the NSURL initWithString method will work!
Also, just so it is clearer for you in the future, you can take advantage of Objective-C's dot notation syntax when you set your quoteNumber string, as follows:
NSString *quoteNumber = self.textBox.text;
Also, you are trying to pass this quoted number into your urlString as a digit (as seen with the %d), remember that quotedNumber is a NSString object, and will crash when you try to pass it to the stringWithFormat method. You must convert the string first to a NSInteger, or NSUInteger.
Please refer to this SO question to how to do that (don't worry it's very easy)!
回答2:
I think you are thinking of NSString's stringWithFormat::
[NSURL URLWithString:[NSString stringWithFormat:@"http://TestSite.com/virdirectory/Webservice1/Service1.asmx/GetQuote?number=%@", quoteNumber]]
Also note the change to %@ for the format specifier, since it is an instance of NSString (not an int)
回答3:
You need to format your string. Try this:
NSString *urlString = [NSString stringWithFormat:@"http://TestSite.com/virdirectory/Webservice1/Service1.asmx/GetQuote?number=%@", quoteNumber];
NSURL *url = [[NSURL alloc] initWithString:urlString];
回答4:
The problem is
[NSURL initWithString:]
requires ONE parameter of NSString type but you passed TWO parameters .
You need to pass a single NSString parameter . Change your code from
NSURL *url = [[NSURL alloc] initWithString:@"http://TestSite.com/virdirectory/Webservice1/Service1.asmx/GetQuote?number=%d", quoteNumber];
to
NSURL *url = [[NSURL alloc] initWithString:[NSString stringWithFormat:@"http://TestSite.com/virdirectory/Webservice1/Service1.asmx/GetQuote?number=%d", quoteNumber]];
来源：https://stackoverflow.com/questions/11321396/why-do-i-get-this-error-when-i-try-to-pass-a-parameter-in-nsurl-in-ios-app