问题
It's pretty simple: Object.entries is supposed to produce and Array of key, value pairs.. As such, I would expected this code to destructure
[{
id: 1,
name: "christian"
},{
id : 2,
name: "bongiorno"
}].map(Object.entries).forEach(([k,v]) => console.log(`${k}: ${v}`));
into producing:
id:1 name:christian
id:2 name:bongiorno
But it doesn't. I get, instead:
id,1: name,christian
id,2: name,bongiorno
What did I miss?
回答1:
The output is correct but your definition is slightly off, you're missing an array level (array of arrays).
Object.entries is supposed to produce an array of arrays of key, value pairs.
console.log(
Object.entries({
id: 1,
name: 'test'
})
)
To achieve what you want, you can just update your log to account for nested arrays:
[{
id: 1,
name: "christian"
},{
id : 2,
name: "bongiorno"
}]
.map(Object.entries)
.forEach(([k, v]) => console.log(
`${k.join(':')} ${v.join(':')}`
));
Or maybe you meant to flatten each array?:
[{
id: 1,
name: "christian"
},{
id : 2,
name: "bongiorno"
}]
.map(Object.entries)
.reduce((arr, curr) => arr.concat(curr), [])
.forEach(([k,v]) => console.log(`${k}: ${v}`));
回答2:
Let's try to drop the map and forEach and see what you did with each of the objects:
let [k, v] = Object.entries({
id: 1,
name: "christian"
});
console.log(`${k}: ${v}`);
let [k, v] = Object.entries({
id : 2,
name: "bongiorno"
});
console.log(`${k}: ${v}`);
Now if we expand the Object.entries call, this becomes
let [k, v] = [
["id", 1],
["name", "christian"]
];
console.log(`${k}: ${v}`);
let [k, v] = [
["id", 2],
["name", "bongiorno"]
];
console.log(`${k}: ${v}`);
which quite accurately reflects what you're seeing - k and v are getting assigned arrays.
You will need to nest two loops:
const arr = [{
id: 1,
name: "christian"
}, {
id: 2,
name: "bongiorno"
}];
for (const obj of arr)
for (const [k, v] of Object.entries(obj))
console.log(k+": "+v);
来源:https://stackoverflow.com/questions/45026162/javascript-array-de-structuring-and-object-entries