Checking if a Hamilton Cycle exists in a dense graph

问题

A few definitions first:

Definition 1

A graph G = (V, E) is called ``dense'' if for each pair of non-adjacent vertices u and v, d(u) + d(v)>=n where n = |V| and d(*) denotes the degree of the vertex *

Definition 2

A ``Hamiltonian cycle'' on G is a sequence of vertices ( vi1, vi2,....vin, vi1 ) such that vil != vih for all l!=h and { vil, vil} is an edge of G.

The problem is: write a program that, given a dense undirected graph G = (V; E) as input, determines whether G admits a Hamiltonian cycle on G and outputs that cycle, if there is one, or outputs ``N'' if there is none.

my solution is to find all the possible paths starting from a source and to check if a path exists that gets back to this source. Unfortunately, this solution is not efficient.

any suggestions? Thank you.

回答1:

According to Ore's theorem, graphs satisfying Definition 1 always have a Hamiltonian cycle, and Palmer's algorithm will give you one in O(n²).

回答2:

The problem is NP-hard. So I would not expect any solution to be much faster than brute-force.

来源：https://stackoverflow.com/questions/11186097/checking-if-a-hamilton-cycle-exists-in-a-dense-graph