Android NotificationListenerService: how to know if user clicked on the notification (opening the related app) or simply deleted it

问题

I'm working with notifications generated by every app (not only mine) on my Android device (android 5.1.1). By extending NotificationListenerService I'm able to know when a push notification is posted (overriding the "onNotificationPosted" method) and when a notification is removed (overriding the "onNotificationRemoved" method).

The problem is that I would like to know how the notification was removed: a) by clicking it (so opening the app) or b) by swyping it (so it is only removed) ?

Is it possible to know it? Thank you in advance!

回答1:

The best way to do it is to get the list of all running processes! So, in the onNotificationRemoved method we can: 1. obtain the list of running processes using the Android Processes library 2. compare each process name with the packageName 3. if the comparison return a true value, we check if the process is in foreground

public void onNotificationRemoved(StatusBarNotification sbn) {
    String packageName = sbn.getPackageName();
    try {
        List<AndroidAppProcess> processes = ProcessManager.getRunningAppProcesses();
        if (processes != null) {
            for (AndroidAppProcess process : processes) {
                String processName = process.name;
                if (processName.equals(packageName)) {
                    if (process.foreground ==true)
                    {
                        //user clicked on notification
                    }
                    else
                    {
                        //user swipe notification
                    }
                }
            }
        }
    }
    catch (Exception e)
    {
        String error = e.toString();
    }
}

来源：https://stackoverflow.com/questions/33088355/android-notificationlistenerservice-how-to-know-if-user-clicked-on-the-notifica