Change display depending on option selected

问题

I want to change 2 different div styles with jQuery. While the value is div1, div1 will be shown. And when the value is div2, div2 will be shown. I guess I can't do it with "if/else" in jQuery.

 <style>
  #div1 { display: block; background-color: red; height:300px; width:300px;}
  $div2 { display: none; background-color: blue; height:300px; width:300px;}
  </style>

  <select id="divit">
    <option value="div1">div1</option>
    <option value="div2">div2</option>
  </select>
<script>
    function displayVals() {
      var divoneValues = $("#divit").val("div1");
      var divtwoValues = $("#divit").val("div2");
      $("#div1").css("display", "none");
       $("#div2").css("display", "block");
    }     
    $("select").change(displayVals);
    displayVals();         

</script>
<div id="div1"></div>
<div id="div2"></div>

</body>
</html>

回答1:

This should do the trick:

<style>
  #div1 { display: block; background-color: red; height:300px; width:300px;}
  #div2 { display: none; background-color: blue; height:300px; width:300px;}
</style>

<select id="divit">
    <option value="div1">div1</option>
    <option value="div2">div2</option>
</select>
<script>
    $("#divit").on('change', function() {
        var sel = $("select").val();
        if (sel=='div1') {
           $("#div1").css("display", "block");
           $("#div2").css("display", "none");
        }else if (sel=='div2') {
           $("#div1").css("display", "none");
           $("#div2").css("display", "block");
        }
    });     
</script>
<div id="div1"></div>
<div id="div2"></div>

FIDDLE

回答2:

$('select').val() returns the value of the selected option. So use a switch like this:

function displayVals() {
    switch ($("#divit").val()) {
        case 'div1':
            $("#div1").show();
            $("#div2").hide();
        break;
        case 'div2':
            $("#div1").hide();
            $("#div2").show();
        break;
    }
}

Demo: http://jsfiddle.net/TimWolla/2KaTK/

回答3:

jQuery is just a Javascript library. You still use Javascript code to access the jQuery library, so you can use any Javascript commands.

function displayVals() {
  var selected = $("#divit").val();
  if (selected == "div1") {
    $("#div1").hide();
    $("#div2").show();
  } else {
    $("#div1").show();
    $("#div2").hide();
  }
}
$("select").change(displayVals);
displayVals();

回答4:

Try this:

$(document).ready(){

    $(#divit).change(function(){
        if($(this).val() == 'div1'){
            $('#div2').hide();
            $('#div1').show();
        }else{
            $('#div1').hide();
            $('#div2').show();
        }
    });

}

回答5:

Like this jsFiddle?

$('#divit').change(function(){
    $('div').hide();
    $('#'+$(this).val()).show();
});

回答6:

<style>
  #div1 { display: block; background-color: red; height:300px; width:300px;}
  #div2 { display: none; background-color: blue; height:300px; width:300px;}
  </style>

  <select id="divit">
    <option value="div1">div1</option>
    <option value="div2">div2</option>
  </select>
<script>
    $('#divit').change(function(){
hideotherdivs($(this).val());
});

function hideotherdivs(div_not_to_hide)
{
$('#div1').hide();
$('#div2').hide();
//add all divs that have to be included in this scheme of hiding and showing
$(eval(div_not_to_hide)).show();
}
</script>
<div id="div1"></div>
<div id="div2"></div>

DEMONSTRATION

回答7:

This will auto hide any non selected options, while will show only the one selected, if you need to put more then two options

<style>
    #div1 { position: absolute; display: block; background-color: red; height:300px; width:300px;}
    #div2 { position: absolute; display: none; background-color: blue; height:300px; width:300px;}
    #div3 { position: absolute; display: none; background-color: green; height:300px; width:300px;}
    #div4 { position: absolute; display: none; background-color: pink; height:300px; width:300px;}
    #div5 { position: absolute; display: none; background-color: aqua; height:300px; width:300px;}
</style>

<select id="divit">
    <option value="div1">div1</option>
    <option value="div2">div2</option>
    <option value="div3">div3</option>
    <option value="div4">div4</option>
    <option value="div5">div5</option>
</select>

<script>

    function displayVals()
    {
        $('select#divit > option').each(function()
        {
            if ($(this).val() == $('select#divit').val())
            {
                $('#'+$(this).val()).css('display', 'block');
            }
            else
            {
                $('#'+$(this).val()).css('display', 'none');
            }
        });
    }     
    $("select").change(displayVals);
    displayVals();         

</script>

<div id="div1"></div>
<div id="div2"></div>
<div id="div3"></div>
<div id="div4"></div>
<div id="div5"></div>

Just a side note: please note that in your code you put a $ in place of a # in your style part for div2
The correct would be #div2 { in place of $div2 {

来源：https://stackoverflow.com/questions/8957284/change-display-depending-on-option-selected