问题
I wish to extract double value completely when I am debugging an application, so that I can use it to construct a test case to feed into my geometry algorithm.
How to extract the double value out-- down to very last decimal places allowed by the double datatypes in C#-- and output it in either debugger windows, or using Console.WriteLine command?
Edit: My problem is that the algorithm that takes the double value as input will only fail if I insist of input the whole double value, right down to the very last digit. And since I want to reproduce it in a test case, that's why I would need such a full representation of the double value.
回答1:
I have a DoubleConverter class which does exactly what you want, by the sounds of it. Use it like this:
string text = DoubleConverter.ToExactString(doubleValue);
You need to make sure you understand that just because the output has a large number of digits, that doesn't mean it has that much precision. You may want to read my article on binary floating point in .NET for more information - or you may be aware of all of this to start with, of course.
Note that if you only want a string value which can be round-tripped, you don't need any extra code - just use the "r" format specifier:
string text = doubleValue.ToString("r");
I agree with Jackson Pope's general approach of using tolerance in equality comparisons for tests, but I do find it useful sometimes to see the exact value represented by a double. It can make it easier to understand why a particular calculation has come out one way or another.
回答2:
Instead of trying to output a binary number as a decimal number to a very large number of decimal places and do an exact comparison, instead do a comparison with an epsilon value that is your acceptable error and set epsilon to be very small. E.g.
double epsilon = Math.Abs(actual - expected);
Assert.That(epsilon, Is.LessThan(0.000000000001);
来源：https://stackoverflow.com/questions/4732680/how-to-output-a-double-value-with-all-the-decimal-places-in-debugger-or-console