问题
In the following code, RegSetValueEx is only writing the first letter of my string. I've tried changing the sizes to just about anything I can think of, and I only ever get the first string. Any help is appreciated.
LPCWSTR path = L"Test String";
size_t size = wclsen(path) * sizeof(wchar_t);
DWORD dwResult = RegSetValueEx(HKEY_LOCAL_MACHINE,
"SOFTWARE\\My App",
0,
REG_SZ,
(LPBYTE)path,
test);
I've tried using path.size() * sizeof(wchar_t) and any number of other sizes I could think of, but nothing seems to work right. Any ideas?
回答1:
RegSetValueEx() expects REG_SZ data to be provided as const TCHAR*, which in your case is const CHAR* per your compiler settings - as evident by the fact that you are able to pass a char* to the second parameter, which means you are actually calling RegSetValueExA(). Since you are providing a const WCHAR* to RegSetValueExA(), the first 0x00 byte gets interpreted as a null terminator, hence only a single character value gets written.
Your options are:
RegSetValueExW(..., (const BYTE*) path, ...CString sPath(path); RegSetValueEx(..., (const BYTE*) (LPCTSTR) sPath, ...Switch project settings to Unicode build
回答2:
Sounds like you haven't defined UNICODE/_UNICODE before compiling, so the zero-byte in your wide string is being interpreted as signaling the end of the string.
Try using RegSetValueExW (and L"SOFTWARE\\My App") instead.
来源:https://stackoverflow.com/questions/22026462/regsetvalueex-only-shows-writes-first-character