问题
I am using clang to compile my code using the c++14 dialect. Take the following example:
class x
{
int _i;
public:
x(int i)
{
this->_i = i;
}
};
void x()
{
}
void f(class x my_x)
{
// Do something here
}
int main()
{
/*
f(x(33)); // Doesn't work
f(class x(33)); // Doesn't work
*/
// This works:
class x my_x(33);
f(my_x);
typedef class x __x;
f(__x(33));
}
Here I have a class named x whose name conflicts with a function with the same name. To distinguish between x the class and x the function, one has to use the class identifier. This works for me in all situations, but I could never find a way to directly call the constructor for x.
In the previous example, I want to provide function f with an x object by building it on the go. However, if I use f(x(33)) it interprets it as an ill-formed call to the function x, and if I use f(class x(33)) it just yields a syntax error.
There are obvious workarounds, but I would like to know if there is anything more elegant than typedefing the class x with a temporary alias or explicitly instantiating an item that will annoy me by living in the whole scope of the calling function while I need it only in the line of the function call.
Maybe there is a simple syntax that I am not aware of?
回答1:
All you need is a pair of parentheses:
f((class x)(33));
Or for more parameters, also use uniform initialization:
f((class x){1, 2, 3});
来源:https://stackoverflow.com/questions/31675004/constructor-of-class-with-conflicting-name