问题
I recently upgraded to numpy 1.9dev. (For improved OpenBlas support).
I have some code that does x-y
Where x and y are samples from a probability distribution.
If the distribution is Bernoulli, then they are boolean.
If the distribution is Gaussian, then they are floats.
where depending on the path followed x and y
might be bools or floats.
I don't have to care as python has duck-typing.
If it can subtract then it is a valid value for x and y
I get this warning:
DeprecationWarning: numpy boolean subtract (the binary
-operator) is deprecated, use the bitwise_xor (the^operator) or the logical_xor function instead.
I have made the warning go away, by casting it to always be a float. This may be a good thing since it makes the code more consistent at a lower level. (Not sold on that as a good thing).
What is the correct action to be taking?
I can't use boolean or bitwise xor as when x and y are floats this will break.
It would be ugly to make the code branch on the type of x and y.
回答1:
maybe you should do:
x=x.astype(numpy.float32)
y=y.astype(numpy.float32)
then
x - y
at least, it works on my case.
回答2:
Here my solution:
z = (x.astype(np.float32) - y.astype(np.float32)).astype(np.bool)
来源：https://stackoverflow.com/questions/24216210/boolean-subtract-deprecationwarning