问题
Is there a better way to do this? Note: part1, part2 and part3 are string variables defined elsewhere (they can be null).
def list = [part1, part2, part3]
list.removeAll([null])
def ans = list.join()
The desired result is a concatenated string with null values left out.
回答1:
You can do this:
def ans = [part1, part2, part3].findAll({it != null}).join()
You might be able to shrink the closure down to just {it} depending on how your list items will evaluate according to Groovy Truth, but this should make it a bit tighter.
Note: The GDK javadocs are a great resource.
回答2:
If you use findAll with no parameters. It will return every "truthful" value, so this should work:
def ans = [part1, part2, part3].findAll().join()
Notice that findAll will filter out empty strings (because they are evaluated as false in a boolean context), but that doesn't matter in this case, as the empty strings don't add anything to join() :)
If this is a simplified question and you want to keep empty string values, you can use findResults{ it }.
回答3:
Alternatively, you can do this as a fold operation with inject:
def ans = [part1, part2, part3].inject('') { result, element ->
result + (element ?: '')
}
This iterates the whole list and concatenates each successive element to a result, with logic to use the empty string for null elements.
回答4:
You could use grep:
groovy:000> list = ['a', 'b', null, 'c']
===> [a, b, null, c]
groovy:000> list.grep {it != null}.join()
===> abc
来源：https://stackoverflow.com/questions/9775951/groovy-string-concatenation-with-null-checks