how can I declare java interface field that implement class should refine that field

问题

How can I declare java interface field that implement class should refine that field ?

for example

public interface IWorkflow{
    public static final String EXAMPLE;// interface field 
    public void reject();
}

// and implement class
public class AbstWorkflow implements IWorkflow
{
    public static final String EXAMPLE = "ABCD"; /*MUST HAVE*/
    public void reject(){}
...
}

Thank you.

回答1:

See section 9.3 of the specification. There is no overriding of fields in interfaces - they are just hidden in some contexts, and ambiguous in others. I'd just stay away. Instead put a getter in the interface (getEXAMPLE())

回答2:

You can't.

Also, an interface can't require static methods to be defined on an implementation either.

The best you can do is this:

public interface SomeInterface {
    public String getExample();
}

来源：https://stackoverflow.com/questions/6543243/how-can-i-declare-java-interface-field-that-implement-class-should-refine-that-f