get current directory of symlink'd php script and not actual php script

问题

I have a script that is symlinked from one folder to another

/var/www/default/index.php

which is symlinked to

/var/www/mysite/index.php

However when i call DIR from mysite the path resolves to the origial path under default. How do i make it return the mysite path (the symlinked folder, not the actual folder)

回答1:

For Web Server requests

dirname($_SERVER['SCRIPT_FILENAME']) will give you what you need.

Failing that $_SERVER['PHP_SELF'] or even REQUEST_URI may have what you need, depending on your server configuration.

For CLI (command Line)

this won't work in cli (command line) scripts as $_SERVER is added by the web server.

Fortunately it's a lot easier with cli scripts (as there is no web server to mess about with things).

All you need is to read the command line that started the script: http://php.net/manual/en/reserved.variables.argv.php. The first argument $argv[0] is always the name that was used to run the script.

回答2:

If you want to get the current path with symlink you can ask your host OS:

$path = exec('pwd');

回答3:

If you are looking for the full unresolved system path of a cli script, SCRIPT_PATH will be insufficient.

php -f symlink/script.php

SCRIPT_FILENAME will contain symlink/script.php

I have created a php/gist that gets the unresolved path to the php file.

Here is the outcome of the function:

 $ php -f subdir/mysymlink/subdir/mysymlink/subdir/mysymlink/app.php
 PWD: /tmp/phpcode                                                                           
 SCRIPT_FILENAME: subdir/mysymlink/subdir/mysymlink/subdir/mysymlink/app.php                 
___FILE__ : /tmp/phpcode/app.php                                                             
 getSymlink(): /tmp/phpcode/subdir/mysymlink/subdir/mysymlink/subdir/mysymlink

来源：https://stackoverflow.com/questions/10525880/get-current-directory-of-symlinkd-php-script-and-not-actual-php-script

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php