Can you register an existing instance of a type in the Windsor Container?

问题

In the Windsor IOC container is it possible to register a type that I've already got an instance for, instead of having the container create it?

回答1:

There is a AddComponentInstance method on the Container's Kernel property.

From the Unit Tests:

[Test]
public void AddComponentInstance()
{
    CustomerImpl customer = new CustomerImpl();

    kernel.AddComponentInstance("key", typeof(ICustomer), customer);
    Assert.IsTrue(kernel.HasComponent("key"));

    CustomerImpl customer2 = kernel["key"] as CustomerImpl;
    Assert.AreSame(customer, customer2);

    customer2 = kernel[typeof(ICustomer)] as CustomerImpl;
    Assert.AreSame(customer, customer2);
}

[Test]
public void AddComponentInstance_ByService()
{
    CustomerImpl customer = new CustomerImpl();

    kernel.AddComponentInstance <ICustomer>(customer);
    Assert.AreSame(kernel[typeof(ICustomer)],customer);
}

[Test]
public void AddComponentInstance2()
{
    CustomerImpl customer = new CustomerImpl();

    kernel.AddComponentInstance("key", customer);
    Assert.IsTrue(kernel.HasComponent("key"));

    CustomerImpl customer2 = kernel["key"] as CustomerImpl;
    Assert.AreSame(customer, customer2);

    customer2 = kernel[typeof(CustomerImpl)] as CustomerImpl;
    Assert.AreSame(customer, customer2);
}

来源：https://stackoverflow.com/questions/90976/can-you-register-an-existing-instance-of-a-type-in-the-windsor-container