Displaying data from arrays in a dynamic table PHP

喜夏-厌秋 提交于 2019-12-23 07:05:39

问题


I have a file with 20 pictures of country artists, and a text file with their websites. I'm trying to display this data in a 4 row 5 column table using PHP.

I try to use a foreach loop that iterates for every 5 elements in the array (to load each row one by one)

foreach(array_chunk($CountryArtists, 5, true) as $Value) {
    <table>
       <tr><td> $CountryArtists[$Value] $ArtistImages[$Value]</td>
    <td> $CountryArtists[$Value] $ArtistImages[$Value]</td>
    <td> $CountryArtists[$Value] $ArtistImages[$Value]</td>
    <td> $CountryArtists[$Value] $ArtistImages[$Value]</td>
    <td> $CountryArtists[$Value] $ArtistImages[$Value]</td></tr>
</table>

Ive been trying to figure out how to load the images into the array, but having no luck. Im starting to think i must put the reference to the file location in the array,but i am not sure.

$colsToDisplay = 5;
$CountryArtists = array("C:\Users\THEFOLDER\images");
$ArtistImages = array("AJackson", "BShelton", "CUnderwood", "DBentley", "DLJones", "DRucker", "JAldean", "JCash", "JJohnson", "JStrait", "KChesney", "LAntebellum", "LDavis", "LRimes", "MLambert", "MMcBride", RTravis", "STwain", TKeith", TMcgraw");
$filename = "C:\Users\THEFOLDER\images";

I'm relatively new to PHP and really just need to know how to load my images and how to make this table show up correctly.

EDIT:

I added echo to the table lines but it just shows echo in the browser output:

" echo " $CountryArtists[$Value] $ArtistImages[$Value]" echo " .$CountryArtists[$Value]. $ArtistImages[$Value]" echo " .$CountryArtists[$Value]. $ArtistImages[$Value]" echo " .$CountryArtists[$Value]. $ArtistImages[$Value]" echo " .$CountryArtists[$Value]. $ArtistImages[$Value]" echo "" } ?>

My code now looks like this:

foreach(array_chunk($CountryArtists, 5, true) as $Value) {
    echo "<table>"
    echo "<tr><td> $CountryArtists[$Value] $ArtistImages[$Value]</td>"
    echo "<td> .$CountryArtists[$Value]. $ArtistImages[$Value]</td>"
    echo "<td> .$CountryArtists[$Value]. $ArtistImages[$Value]</td>"
    echo "<td> .$CountryArtists[$Value]. $ArtistImages[$Value]</td>"
    echo "<td> .$CountryArtists[$Value]. $ArtistImages[$Value]</td></tr>"
    echo "</table>"
}

I feel like I'm doing strong wrong, would be so grateful to have it pointed out to me.

FULL FILE

 <!DOCTYPE HTML>
<html>
<body>

<?php
$ArtistImages = array("AJackson", "BShelton", "CUnderwood", "DBentley", "DLJones", "DRucker", "JAldean", "JCash", "JJohnson", "JStrait", "KChesney", "LAntebellum", "LDavis", "LRimes", "MLambert", "MMcBride", "RTravis", "STwain", "TKeith", "TMcgraw");
$count  =   count($ArtistImages);
$cols   =   6;
$div    =   (int) $count / (int)$cols;
$diff   =   ceil($div);
echo
$fin    =   $cols * $diff;

$a = 1;
echo '<table>';
for($i = 0; $i < $fin; $i++) {
    if($a == 1)
        echo "\t<tr>".PHP_EOL;

    $artist =   (!empty($ArtistImages[$i]))? $ArtistImages[$i]: "";
    echo "\t\t".'<td>'.$artist.'</td>'.PHP_EOL;

    if($a == $cols) {
            echo "\t</tr>".PHP_EOL;
            $a=0;
        }

    $a++;
}
echo '</table>';
?>

</body>
</html>

回答1:


I think you may be looking for something similar to this algorithm. It adds a row every 5 values. You will want to do a divisor make it ceil() to make it add any required empty cells. You can do this foreach if you do <ul> and <li> and use CSS to make them display like a table. Then you don't need to calculate extra cells.

$i = 1;
echo '<table>';
foreach($array as $value) {
    if($i == 1)
        echo "<tr>";

    echo '<td>'.$value.'</td>';

    if($i == 5) {
            echo "</tr>";
            $i=0;
        }

    $i++;
}
echo '</table>';

EDIT:

Here is a more practical version based on yours:

$ArtistImages = array("AJackson", "BShelton", "CUnderwood", "DBentley", "DLJones", "DRucker", "JAldean", "JCash", "JJohnson", "JStrait", "KChesney", "LAntebellum", "LDavis", "LRimes", "MLambert", "MMcBride", "RTravis", "STwain", "TKeith", "TMcgraw");

// Count total artists in array
$count  =   count($ArtistImages);
// Choose how many to display per row
$cols   =   6;
// Divide the total by the columns
$div    =   (int) $count / (int)$cols;
// Round up (incase the number will produce empty cells
$diff   =   ceil($div);
// Mulitply the final numbers
$fin    =   $cols * $diff;
// Create an autoincrementer to keep track of next rows
$a = 1;
echo '<table>'.PHP_EOL;
for($i = 0; $i < $fin; $i++) {
    if($a == 1)
        echo "\t<tr>".PHP_EOL;
    // You need to see if this artist is populated. If not, make empty
    // If left without this it will have a warning saying not exists
    $artist =   (!empty($ArtistImages[$i]))? $ArtistImages[$i]: "";
    echo "\t\t".'<td>'.$artist.'</td>'.PHP_EOL;
    if($a == $cols) {
            echo "\t</tr>".PHP_EOL;
            $a=0;
        }

    $a++;
}
echo '</table>';



回答2:


In the php file you need to echo the data you want. However if you in the php file you can close php like this. ? > And write html code. When you want to display php attributes you again need to open a php like this: and continue like this... Php fcan only return string or json data Let me know if it work for you....



来源:https://stackoverflow.com/questions/33202569/displaying-data-from-arrays-in-a-dynamic-table-php

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!