问题
The form is validated before submit with this plugin. And submitted as shown in the code:
jQuery.validator.setDefaults({
submitHandler: function(){
jQuery("form").submit(function(e) {
e.preventDefault();
jQuery.post(base_url + "blog/ajax_comment", { author: jQuery("#author").val(), email: jQuery("#email").val(), url: jQuery("#url").val(), message: jQuery("#message").val() , post_ID: jQuery("#post_ID").val(), not: jQuery("#not").val() }, function (data) {
//do stuff here
});
});
}
});
jQuery().ready(function() {
// validate the comment form when it is submitted
jQuery("#commentform").validate();
});
In order to be submitted, I need to press the submit button twice. I am kind of new to jQuery, and I can't really tell why is that. Is there an easy way to fix this?
回答1:
The submitHandler
is already overriding the default event, so just place the code for the ajax submission in there:
jQuery.validator.setDefaults({
submitHandler: function(){
jQuery.post(base_url + "blog/ajax_comment", { author: jQuery("#author").val(), email: jQuery("#email").val(), url: jQuery("#url").val(), message: jQuery("#message").val() , post_ID: jQuery("#post_ID").val(), not: jQuery("#not").val() }, function (data) {
//do stuff here
});
}
});
If you elements have name
attributes that match their IDs though, just use .serialize(), like this:
jQuery.validator.setDefaults({
submitHandler: function(form){
jQuery.post(base_url + "blog/ajax_comment", jQuery(form).serialize(), function (data) {
//do stuff here
});
}
});
What's happening with your current code is that in the submit
handler, it's attaching a new submit
handler for next time, rather than actually running your code. Instead, just run your code directly in the submitHandler
callback.
来源:https://stackoverflow.com/questions/3846930/need-to-press-submit-twice-for-submitting-a-form-with-ajax-jquery-validation-pl