问题
I'm trying to create an inbox for messaging between users.
Here are the following tables:
Messsages
Id | Message_from | message_to | message
1 | 2 | 1 | Hi
2 | 2 | 1 | How are you
3 | 1 | 3 | Hola
4 | 4 | 1 | Whats up
5 | 1 | 4 | Just Chilling
6 | 5 | 1 | Bonjour
Users
Id | Name
1 | Paul
2 | John
3 | Tim
4 | Rob
5 | Sarah
6 | Jeff
I'd like to display an inbox showing the list of users that the person has communicated and the last_message from either users
Paul's Inbox:
Name | user_id | last_message
Sarah| 5 | bonjour
Rob | 4 | Just Chilling
Tim | 3 | Hola
John | 2 | How are you
How do I do this with Active Records?
回答1:
This should be rather efficient:
SELECT u.name, sub.*
FROM (
SELECT DISTINCT ON (1)
m.message_from AS user_id
, m.message AS last_message
FROM users u
JOIN messages m ON m.message_to = u.id
WHERE u.name = 'Paul' -- must be unique
ORDER BY 1, m.id DESC
) sub
JOIN users u ON sub.user_id = u.id;
Compute all users with the latest message in the subquery sub using DISTINCT ON. Then join to
table users a second time to resolve the name.
Details for DISTINCT ON:
Select first row in each GROUP BY group?
Aside: Using "id" and "name" as column names is not a very helpful naming convention.
回答2:
How about this:
@received_messages = current_user.messages_to.order(created_at: :desc).uniq
If you want to include messages from the user as well, you might have to do a union query, or two queries, then merge and join them. I'm just guessing with some pseudocode, here, but this should set you on your way.
received_messages = current_user.messages_to
sent_messages = current_user.messages_from
(received_messages + sent_messages).sort_by { |message| message[:created_at] }.reverse
This type of logic is belongs to a model, not the controller, so perhaps you can add this to the message model.
回答3:
scope :ids_of_latest_per_user, -> { pluck('MAX(id)').group(:user_id) }
scope :latest_per_user, -> { where(:id => Message.latest_by_user) }
Message.latest_per_user
来源:https://stackoverflow.com/questions/23728320/display-latest-messages-from-messages-table-group-by-user