问题
I downloaded some files from internet. In the name field of those files each ' ' character is replaced by "%20". I want to rename all of those but number of files is too high. So manual approach would be clumsy. I know from command line with regular expression this can be done but I am not very familiar with it. So little help is needed.
Summary is, I want to rename all files in a directory by replacing all "%20" patterns with " ". How can I do it?
Sample:
17%20Clipping.cpp --> 17 Clipping.cpp
14%20Mouse%20(Button)%20Listener.cpp --> 14 Mouse (Button) Listener.cpp
回答1:
you can rename a group of files using command rename that accept regular expression
For example, to rename all files matching "*.bak" to strip the extension, you might say
rename 's/\.bak$//' *.bak
To translate uppercase names to lower, you'd use
rename 'y/A-Z/a-z/' *
and your answer:
rename 's/%20/ /' *.cpp
回答2:
I would recommend against putting spaces in filenames (maybe use underscore instead). Regardless, here is a command that will do it:
for i in *%20*; do new=$(echo $i|sed 's/%20/ /'); echo mv $i "$new"; done
In its current form it merely prints the commands it would execute. Once you're sure it does what you want, remove the echo.
As @ronmrdechai suggests, the following is an improvement:
for i in *%20*; do echo mv $i "${i/\%20/ }"; done
The backslash is needed in the pattern because % is a metacharacter (match at end) in this case.
来源：https://stackoverflow.com/questions/20251042/rename-multiple-files-with-regular-expression