Action Script 3 XML date format

≯℡__Kan透↙ 提交于 2019-12-23 04:56:48

问题


I am creating an XML based screensaver using Flash CS3, everything works fine. However, on the XML output file the date output format remains unformatted (YYYY-MM-DD T00:00:00+00:00). Ideally, a UK date (DD/MM/YYYY) format would be output.

Below is a sample of the ActionScript code driving an XML file

// Load up variables with XML element data

var item_data:Array = new Array();
item_data[0] = xml_item.id;
item_data[1] = xml_item.Product_Name;
item_data[2] = xml_item.Product_Language;
item_data[3] = xml_item.dateCreated;
item_data[4] = xml_item.antDeadlineDate;
item_data[5] = xml_item.comments;
item_data[6] = xml_item.webPdf;
item_data[7] = xml_item.conCheck;

// Set output variable

output = "<b>Job ID</b>:" + item_data[0] + "\n";
output += "<b>Product Name</b>: " + item_data[1] + "\n";
output += "<b>Language</b>: " + item_data[2] + "\n";
output += "<b>Date Created</b>: " + item_data[3] + "\n";
output += "<b>Anticipated Deadline</b>: " + item_data[4] + "\n";
output += "<b>Comments</b>: " + item_data[5] + "\n";
output += "<b>PDFs created</b>: " + item_data[6] + "\n";
output += "<b>Controller Check</b>: " + item_data[7] + "\n\n\n\n";

回答1:


you can use also Regular Expression

var xmlDateTime:RegExp = /([0-9]{4})-(0[0-9]|1[012])-([012][0-9]|3[01])T([01][0-9]|2[0-3])(:[0-5][0-9]){2}(.[0-9]{3}){0,1}(\+|-)([01][0-9]|2[0-3]):[0-5][0-9]/g;
var dateString = xml_item.dateCreated.toString().replace(xmlDateTime, "$3/$2/$1");



回答2:


To convert a date string in this format YYYY-MM-DD T00:00:00+00:00 to this format DD/MM/YYYY you can do this:

var dateOld:String = '1999-01-05 T00:00:00+00:00';
var dateParts:Array = dateOld.substring(0, 10).split('-');
var dateNew:String = dateParts[2] + '/' + dateParts[1] + '/' + dateParts[0];


来源:https://stackoverflow.com/questions/15140301/action-script-3-xml-date-format

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