Minimal C/C++ program that segfaults? [duplicate]

问题

This question already has answers here:

What is the easiest way to make a C++ program crash? (29 answers)

Closed 5 years ago.

I'm trying to set up the way my server handles core dumps. In order to test it, I'd need a program that always segfaults.

Is there a simple example program that always segfaults?

回答1:

main;

is portable, and segfault in 5chars.

回答2:

main() { *(int *)0xdeadbeef = 37; } should do it.

回答3:

try this:

long* ptr = 0x0; //-- you can also use other random values and likely you will segfault
printf("%f", *ptr);

回答4:

You can try:

main() {
char *p = NULL;
char c = *p;
}

回答5:

this should die:

int main() {
    char *die;
    printf("%d",(int *)die * 200);
    return 0;
}

edit:

int main() {
    char *die;
    int killer = 200;
    while(1) {
       printf("%d",(int *)die * killer);
       killer = killer * killer;
    }
    return 0;
}

来源：https://stackoverflow.com/questions/12404759/minimal-c-c-program-that-segfaults