问题
How to hide first/second div with jQuery?
Div can not get id/class!
<body>
<div>
<p>ssssssss</p>
</div>
<div>
<p>ttttttttt></p>
</div>
<div>
<p>fffff</p>
</div>
</body>
回答1:
To hide the first <div> element, do:
$("div:eq(0)").hide();
To hide the second <div> element, do:
$("div:eq(1)").hide();
To hide both the first and the second <div> elements, do:
$("div:lt(2)").hide();
回答2:
$('div:lt(2)').hide();
回答3:
$("body div:nth-child(1)").hide(); perhaps? untested
HTML markup is needed to help further
edit - ah ha, code block fail - my code still stands but i suspect there's a better way
回答4:
You can use pseudo-selectors :first and :nth(n)... Note that nth(n) is zero-based. So :nth(0) is equivalent to :first.
$('div:first').hide();
$('div:nth(1)').hide();
回答5:
to hide child div 1 and child div 2 (or 3 or 4)
$('body div:nth-child(1),body div:nth-child(2)').hide();
nth-child is the offset and the comma seperates out which ones.. in case you wanted to keep div# 2 it could be
$('body div:nth-child(1),body div:nth-child(3)').hide();
来源：https://stackoverflow.com/questions/4319279/how-to-hide-div-that-without-id-class-by-jquery