问题
I'm trying to setup a basic JPA insert test. But nothing is saved in the DB. DB is Postgresql. Hibernate is used as Persistence provider.
Many thanks in advance.
@Entity
public class Currency {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
protected Integer id;
@Column
private String code;
@Column
private String name;
...
}
The CRUD class :
@Repository
@Scope(BeanDefinition.SCOPE_PROTOTYPE)
@Transactional(propagation = Propagation.REQUIRED)
public class CRUDServiceBean implements CRUDService {
@PersistenceContext(type = PersistenceContextType.EXTENDED)
private EntityManager entityManager;
public EntityManager getEntityManager() {
return entityManager;
}
public <T extends BaseEntity> T persistAndCommit(T t) {
entityManager.persist(t);
entityManager.refresh(t);
entityManager.getTransaction().commit();
return t;
}
...
...
}
Base class for all tests:
@RunWith(SpringJUnit4ClassRunner.class)
@Configurable(autowire = Autowire.BY_NAME)
@ContextConfiguration(locations = { "classpath:context-test.xml" })
public class BaseTest {
}
The test class:
public class CurrencyCreateTest extends BaseTest {
@Autowired
CRUDService crudService;
@Test
@Transactional(propagation = Propagation.REQUIRES_NEW)
public void createCurrency() throws Exception {
Currency currency = new Currency();
currency.setCode("EUR");
currency.setName("Euro");
currency = crudService.persistAndCommit(currency);
}
}
context-test.xml :
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:task="http://www.springframework.org/schema/task"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-4.0.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-4.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-4.0.xsd">
<context:component-scan base-package="com.chartinvest"/>
<bean id="contextApplicationContextProvider" class="com.chartinvest.util.ApplicationContextProvider"></bean>
<!-- the parent application context definition for the springapp application -->
<!-- dataSource -->
<bean id="dataSourceFinance" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName"><value>org.postgresql.Driver</value></property>
<property name="url"><value>jdbc:postgresql://localhost/db_finance_test</value></property>
<property name="username"><value>postgres</value></property>
<property name="password"><value>xxxxxxxx</value></property>
</bean>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory" />
</bean>
<bean id="entityManagerFactory"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="persistenceUnitName" value="mypersistenceunit" />
<property name="dataSource" ref="dataSourceFinance" />
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
<property name="showSql" value="true" />
<property name="databasePlatform" value="org.hibernate.dialect.PostgreSQLDialect" />
</bean>
</property>
<property name="jpaPropertyMap">
<map>
<entry key="hibernate.dialect" value="org.hibernate.dialect.PostgreSQLDialect"/>
</map>
</property>
</bean>
<!-- Enable the configuration of transactional behavior based on annotations -->
<tx:annotation-driven transaction-manager="transactionManager"/>
</beans>
回答1:
If your test passed successfully and you do not get any exception so use @TransactionConfiguration(defaultRollback=false) per test class or use @Rollback(false) per test method. Transactional tests will rollback by default in spring test context.
@RunWith(SpringJUnit4ClassRunner.class)
@ContextConfiguration(locations={
"test-context.xml"})
@TransactionConfiguration(defaultRollback=false)
@Transactional
public class SampleCrudTest {
@Autowired
private SampleCrud sampleCrud;
@Before
public void onSetUpInTransaction() throws Exception {
//Populate Test Data
}
@Test
public void registerSample() {
Sample sample = new Sample("foo");
sampleCrud.save(sample);
assertNotNull(sample.getId());
}
}
回答2:
I noticed the following in the log file:
java.lang.IllegalStateException: Cannot execute getTransaction() on a container-managed EntityManager
at
...
...
So, I removed
entityManager.getTransaction().commit();
from the method persistAndCommit(T) in CRUDServiceBean
This removed the exception, and there are no other exceptions anymore. The output of the test shows the following:
Hibernate: insert into Currency (code, name) values (?, ?)
However, no record has been written in the table CURRENCY.
It's like after the test finishes, Hibernate removes the inserted record.
回答3:
Its working for me, Ensure you initiate the transaction and commit the transaction.
public Transaction startTransaction(Session session) throws HibernateException {
return session.beginTransaction();
}
...... your test code goes here......
public void endTransaction(Session session) throws HibernateException {
if (session != null) {
session.getTransaction().commit();
}
}
回答4:
You can annotate the test (or the test base class) with @Rollback(false)
e.g:
@DataJpaTest
@RunWith(SpringRunner.class)
@Rollback(false)
abstract class RepositoryTest {
...
}
class UserReportitoryTest extends RepositoryTest {
@Autowired
UserRepository repository;
@Test
void it_should_save_the_user() {
repository.save(user);
}
}
来源:https://stackoverflow.com/questions/32922136/persist-commit-not-working-in-test-environment-with-spring-jpa-junit