Get user name with Apache CXF 2.4 JAX-RS and Spring Security 3.2

问题

I get the user name in my JAX-RS resource with SecurityContextHolder and that works:

@Path("/myresource")
public class MyResoure {

     @Get
     public String getUserName() {
          return SecurityContextHolder.getContext().getAuthentication().getName();
     }
}

But I want to inject the SecurityContext into a class field (to write JUnit tests). I tried some documented ways:

With javax.ws.rs.core.SecurityContext I get a NullPointerException, because the securityContext is always null.

@Path("/myresource")
public class MyResoure {

    @Context
    private javax.ws.rs.core.SecurityContext securityContext;

    @Get
    public String getUserName() {
        return securityContext.getUserPrincipal().getName();
    }
}

With org.apache.cxf.security.SecurityContext (see Apache CXF documentation) I get a NullPointerException, because the securityContext.getUserPrincipal() is always null.

@Path("/myresource")
public class MyResoure {

    @Context
    private org.apache.cxf.security.SecurityContext securityContext;

    @Get
    public String getUserName() {
        return securityContext.getUserPrincipal().getName();
    }
}

With org.apache.cxf.jaxrs.ext.MessageContext (see Apache CXF documentation) I get a NullPointerException, because the messageContext.getSecurityContext().getUserPrincipal() is always null.

@Path("/myresource")
public class MyResoure {

    @Context
    private org.apache.cxf.jaxrs.ext.MessageContext messageContext;

    @Get
    public String getUserName() {
        return messageContext.getSecurityContext().getUserPrincipal().getName();
    }
}

With javax.servlet.http.HttpServletRequest I get a NullPointerException, because the httpServletRequest.getUserPrincipal() is always null.

@Path("/myresource")
public class MyResoure {

    @Context
    private javax.servlet.http.HttpServletRequest httpServletRequest;

    @Get
    public String getUserName() {
        return httpServletRequest.getUserPrincipal().getName();
    }

回答1:

To get the user name with

• javax.ws.rs.core.SecurityContext,
• org.apache.cxf.security.SecurityContext,
• org.apache.cxf.jaxrs.ext.MessageContext or
• javax.servlet.http.HttpServletRequest

I had to add the SecurityContextHolderAwareRequestFilter to my springSecurityFilterChain.

Spring configuration:

<bean id="springSecurityFilterChain" class="org.springframework.security.web.FilterChainProxy">
    <security:filter-chain-map path-type="ant">
        <security:filter-chain pattern="/**" filters="securityContextPersistenceFilter,authenticationProcessingFilter,securityContextHolderAwareRequestFilter,anonymousProcessingFilter,exceptionTranslationFilter,filterSecurityInterceptor" />
    </security:filter-chain-map>
</bean>

With Security Namespace Configuration or Java Configuration the filter is added by default, see Spring Security documentation:

• servlet-api-provision Provides versions of HttpServletRequest security methods such as isUserInRole() and getPrincipal() which are implemented by adding a SecurityContextHolderAwareRequestFilter bean to the stack. Defaults to true.

回答2:

I found some solutions for my JUnit problem:

• Setting SecurityContext in SecurityContextHolder (see https://stackoverflow.com/a/5703170)

  JUnit test code:

  public class MyResourceTest {
  
      private SecurityContext securityContextMock = mock(SecurityContext.class);
  
      @Before
      public void setUp() {
          SecurityContextHolder.setContext(securityContextMock);
      }
  
      @After
      public void tearDown() {
          SecurityContextHolder.clearContext();
      }
  }
  

• Wrapping SecurityContextHolder (see https://stackoverflow.com/a/5702970)

  Wrapper code:

  public class MySecurityContextHolder {
      public SecurityContext getContext() {
          return SecurityContextHolder.getContext();
      }
  }
  

  Resource code:

  @Path("/myresource")
  public MyResource {
  
      private MySecurityContextHolder mySecurityContextHolder;
  
      @Get
      public String getUserName() {
           return mySecurityContextHolder.getContext().getAuthentication().getName();
      }
  }
  

• Using SecurityContextHolderStrategy (see SEC-1188)

  Spring configuration:

  <bean id="myResource" class="MyResource">
      <property name="securityContextHolderStrategy" >
          <bean class="org.springframework.security.context.SecurityContextHolder" factory-method="getContexHolderStrategy">
          </bean>
      </property>
  </bean>
  

  Resource code:

  @Path("/myresource")
  public MyResource {
  
      private SecurityContextHolderStrategy securityContextHolderStrategy;
  
      @Get
      public String getUserName() {
           return securityContextHolderStrategy.getContext().getAuthentication().getName();
      }
  }
  

• Using PowerMock (see https://stackoverflow.com/a/5703197/5277820)

来源：https://stackoverflow.com/questions/32796368/get-user-name-with-apache-cxf-2-4-jax-rs-and-spring-security-3-2