问题
I am sure there is a more elegant way of writing the following macro which prints the name and value of a variable:
def mprintx(c: Context)(linecode: c.Expr[Any]): c.Expr[Unit] = {
import c.universe._
val namez = (c.enclosingImpl match {
case ClassDef(mods, name, tparams, impl) =>
c.universe.reify(c.literal(name.toString).splice)
case ModuleDef(mods, name, impl) =>
c.universe.reify(c.literal(name.toString).splice)
case _ => c.abort(c.enclosingPosition, "NoEnclosingClass")
}).toString match {
case r_name(n) => n
case _ => "Unknown?"
}
val msg = linecode.tree.productIterator.toList.last.toString.replaceAll("scala.*\\]", "").replaceAll(namez+"\\.this\\.", "").replaceAll("List", "")
reify(myPrintDln(c.Expr[String](Literal(Constant(msg))).splice+" ---> "+linecode.splice))
}
def myPrintIt(linecode: Any) = macro mprintx
called by the following program:
object Zabi2 extends App {
val l = "zab"
val kol = 345
var zub = List("2", 89)
val zubi = List(zub,l,kol)
printIt(l)
printIt(l, kol, (l, zub),zubi)
}
which prints:
l ---> zab
(l, kol, (l, zub), zubi) ---> (zab,345,(zab,List(2, 89)),List(List(2, 89), zab, 345))
Thanks in advance for your help.
来源:https://stackoverflow.com/questions/21857130/how-to-print-variable-name-and-value-using-a-scala-macro