Error when mocking interfaces in PHP using Mockery

坚强是说给别人听的谎言 提交于 2019-12-22 04:46:22

问题


I have run into a problem when mocking Interfaces using Mockery in PHP (im using the laravel framework but I'm not sure this is relevant.

I have defined an interface

<?php namespace MyNamespace\SomeSubFolder;

interface MyInterface {

    public function method1();

}

And I have a class that typehints that interface on one of the methods...

<?php namespace MyNamespace\SomeSubFolder;

use MyNamespace\SomeSubFolder\MyInterface;

class MyClass {

    public function execute(MyInterface $interface)
    {
         //does some stuff here

    }
}

...and I am trying to test MyClass. I have created a test that looks something like this:

public function testExecute()
{

    $mock = Mockery::mock('MyNamespace\SomeSubFolder\MyInterface');

    $mock->shouldReceive('method1')
         ->andReturn('foo');

    $myClass = new MyClass();

    $myClass->execute($mock);

}

When I run the test I receive the message

'ErrorException: Argument 1 passed to MyClass::execute must be an instance of MyNamespace\SomeSubFolder\MyInterface, instance of Mockery_123465456 given....'

I have no idea why.

Within the test I have tried the following :

$this->assertTrue(interface_exists('MyNamespace\SomeSubFolder\MyInterface'));

$this->assertTrue($mock instanceof MyInterface);

and both return true, so it appears as if I have created and instance that implements the interface, but when I call the method on the class it disagrees. Any ideas???


回答1:


You should call mock() method at the and of mock declaration.

$mock = Mockery::mock('MyNamespace\SomeSubFolder\MyInterface');

$mock->shouldReceive('method1')
     ->andReturn('foo')
     ->mock();



回答2:


I think the problem is with PHP class loading. Your 'MyNamespace\SomeSubFolder\MyInterface' class isn't available from your test file.

You'll need to modify your composer.json to autoload that namespace or you'll need a require_once('path/to/file/containing/namespace/MyInterface.php') at the top of your test.

Although, when you did try the interface_exists it seemed to pass. It could also be that you misspelled your namespaced class when you mocked it. I've made that mistake as well.

In any case, Mockery isn't able to see that the class exists so it's just inventing one.

Can you provide your full test source?



来源:https://stackoverflow.com/questions/19479052/error-when-mocking-interfaces-in-php-using-mockery

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!