Replace column values in a CSV file with awk

问题

I have this file

error.log

[00:00:00.284],501,

[00:00:00.417],5,5294100071980

[00:00:02.463],501,

[00:00:05.169],501,

[00:00:05.529],501,

[00:00:05.730],501,

so, if the field $3 its empty i want to print "No value"

Im trying this code

awk '{{FS=","} if($3=="") {print $1,$2,"No value"}}'

But it prints

>[00:00:00.284] 501 No value
>[00:00:02.463] 501 No value
>[00:00:05.169] 501 No value
>[00:00:05.529] 501 No value
>[00:00:05.730] 501 No value
>[00:00:07.193] 501 No value
>[00:00:09.899] 501 No value
>[00:00:31.312] 501 No value

回答1:

awk -F ',' -v OFS=',' '$1 { if ($3=="") $3="No value"; print}' in.txt

Passes the field separator via the -F option.
Variable OFS, the output-field separator, is set to ,, so that output fields are also separated by ,.
Pattern $1 ensures that only non-empty lines are processed (that is, the associated action is only executed if the first field is non-empty) - if your input file has no empty lines, you can remove this pattern.
If the 3rd field is empty, it is assigned string "No value"
Finally, the line (with the potentially modified 3rd field) is output.

The above is how I suggest you approach the problem, but here are the problems with your original command:

{{FS=","}... Inside your single action - which due to not having a preceding pattern is executed for every input line - you set variable FS for every line - which is not only unnecessary but too late, because the first input line has already been parsed by that time (thanks, @EdMorton) - either set it in a BEGIN block (BEGIN { FS="," }) or, as in my answer, with command-line option -F (-F ',').
if($3=="") {...}
You only produce output if field $3 is empty - presumably, though, you want to output all lines, so with this approach you'd need an else branch (to print unmodified lines).
print $1,$2,"No value"
The , chars. here are part of the syntax - they simply separate the arguments passed to print. Given separate arguments, print concatenates them with the value of the special OFS variable, whose value is a single space by default; to use , instead, you have to assign it to OFS - again, either in a BEGIN block or via the -v option (-v OFS=',').

回答2:

You should post some expected output but I THINK what you want is:

awk 'BEGIN{FS=OFS=","} NF{print $1, $2, ($3=="" ? "No value" : $3)}' file

回答3:

With this file

cat file
[00:00:00.284],501,
[00:00:00.417],5,5294100071980
[00:00:02.463],501,
[00:00:05.169],501,
[00:00:05.529],501,
[00:00:05.730],501,

This awk should do

awk -F, '$3=="" {$3="No value"}1' OFS=, file
[00:00:00.284],501,No value
[00:00:00.417],5,5294100071980
[00:00:02.463],501,No value
[00:00:05.169],501,No value
[00:00:05.529],501,No value
[00:00:05.730],501,No value

来源：https://stackoverflow.com/questions/21641452/replace-column-values-in-a-csv-file-with-awk

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