How to find nearest location using latitude and longitude from a json data

问题

I'm trying to make a website that ask for user's location then find the closest location (100m radius) from it's position using GeoLocation and display the result in HTML.

What I have tried.

$.getJSON("places.json", function (data) {
        for (var i = 0; i < data.length; i++) {
            if ((data[i].lat - poslat) > 0.00200 || (data[i].lng - poslng) > 0.00200) {
            return data[i];
        }

        html += '<p>' + data[i].location + ' - ' + data[i].code + '</p>';
        $('#nearbystops').append(html);
    }
});

places.json

[
{
"code": "0001",
"lat": "1.28210155945393",
"lng": "103.81722480263163",
"location": "Stop 1"
},
{
"code": "0003",
"lat": "1.2777380589964",
"lng": "103.83749709165197",
"location": "Stop 2"
},
{
"code": "0002",
"lat": "1.27832046633393",
"lng": "103.83762574759974",
"location": "Stop 3"
}
]

Thank you in advance! :)

回答1:

To calculate distance between two co-ordinates, you can't just subtract the values. That's fine but it gives you the co-ordinates that are within a square. This may be suitable but mostly people do tend to want to search locations by radius. This function will do that...

function distance(lat1, lon1, lat2, lon2, unit) {
    var radlat1 = Math.PI * lat1/180
    var radlat2 = Math.PI * lat2/180
    var theta = lon1-lon2
    var radtheta = Math.PI * theta/180
    var dist = Math.sin(radlat1) * Math.sin(radlat2) + Math.cos(radlat1) * Math.cos(radlat2) * Math.cos(radtheta);
    if (dist > 1) {
        dist = 1;
    }
    dist = Math.acos(dist)
    dist = dist * 180/Math.PI
    dist = dist * 60 * 1.1515
    if (unit=="K") { dist = dist * 1.609344 }
    if (unit=="N") { dist = dist * 0.8684 }
    return dist
}

It's a common piece of code which I copied from here...

https://www.geodatasource.com/developers/javascript

And here it is, used in your example...

function distance(lat1, lon1, lat2, lon2, unit) {
    	var radlat1 = Math.PI * lat1/180
    	var radlat2 = Math.PI * lat2/180
    	var theta = lon1-lon2
    	var radtheta = Math.PI * theta/180
    	var dist = Math.sin(radlat1) * Math.sin(radlat2) + Math.cos(radlat1) * Math.cos(radlat2) * Math.cos(radtheta);
    	if (dist > 1) {
    		dist = 1;
    	}
    	dist = Math.acos(dist)
    	dist = dist * 180/Math.PI
    	dist = dist * 60 * 1.1515
    	if (unit=="K") { dist = dist * 1.609344 }
    	if (unit=="N") { dist = dist * 0.8684 }
    	return dist
    }

    var data = [{
        "code": "0001",
        "lat": "1.28210155945393",
        "lng": "103.81722480263163",
        "location": "Stop 1"
    }, {
        "code": "0003",
        "lat": "1.2777380589964",
        "lng": "103.83749709165197",
        "location": "Stop 2"
    }, {
        "code": "0002",
        "lat": "1.27832046633393",
        "lng": "103.83762574759974",
        "location": "Stop 3"
    }];

    var html = "";
    var poslat = 1.28210155945393;
    var poslng = 103.81722480263163;

    for (var i = 0; i < data.length; i++) {
        // if this location is within 0.1KM of the user, add it to the list
        if (distance(poslat, poslng, data[i].lat, data[i].lng, "K") <= 0.1) {
            html += '<p>' + data[i].location + ' - ' + data[i].code + '</p>';
        }
    }

    $('#nearbystops').append(html);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div id="nearbystops"></div>

回答2:

get current user's location using HTML5 geolocation and find nearest location within 100 meters.

include and use below google maps libs

<script type="text/javascript" src="http://maps.google.com/maps/api/js?sensor=false&libraries=geometry"> </script>

Snippet

//calculates distance between two points in km's
function calcDistance(p1, p2) {
  return (google.maps.geometry.spherical.computeDistanceBetween(p1, p2) / 1000).toFixed(2);
}

function getPosition(position) {
  var userPosition = {
    lat: position.coords.latitude,
    lng: position.coords.longitude
  };

  $.getJSON("places.json", function(data) {
    for (var i = 0; i < data.length; i++) {

      var p1 = new google.maps.LatLng(userPosition.lat, userPosition.lng);
      var p2 = new google.maps.LatLng(data[i].lat, data[i].lng);

      var distance = calcDistance(p1, p2) * 1000;

      if ((distance * 1000) <= 100) {
        html += '<p>' + data[i].location + ' - ' + data[i].code + '</p>';
        $('#nearbystops').append(html);
      }

    }

  })
}

// get user's current latitude & longitude
function getLocation() {
  if (navigator.geolocation) {
    navigator.geolocation.getCurrentPosition(getPosition);
  } else {
    alert("Geolocation is not supported by this browser.");
  }
}

getLocation();

回答3:

To calculate the distance between two points (latitude, longitude), implemented a function of haversine formula in typescript.

//There are 6200 points in the JSON file
import data from './json/test.json';

let radians = function (degree: number) {

  // degrees to radians
  let rad: number = degree * Math.PI / 180;

  return rad;
}

const haversine = (lat1: number, lon1: number, lat2: number, lon2: number) => {

  let dlat, dlon, a, c, R: number;

  R = 6372.8; // km
  dlat = radians(lat2 - lat1);
  dlon = radians(lon2 - lon1);
  lat1 = radians(lat1);
  lat2 = radians(lat2);
  a = Math.sin(dlat / 2) * Math.sin(dlat / 2) + Math.sin(dlon / 2) * Math.sin(dlon / 2) * Math.cos(lat1) * Math.cos(lat2)
  c = 2 * Math.asin(Math.sqrt(a));
  return R * c;
}

let test = function () {
  const keys = Object.keys(data);

  let count: number = keys.length;
  for (var _i = 0; _i < count; _i++) {
    var _dummy: number = haversine(
      36.12, -86.67, data[_i].position.lat, data[_i].position.lng);
  }

}

来源：https://stackoverflow.com/questions/51819224/how-to-find-nearest-location-using-latitude-and-longitude-from-a-json-data

标签

javascript

html

json

geolocation