org.hibernate.HibernateException: save is not valid without active transaction

问题

I am creating JSF application and using some hibernate stuff in it. All I want to do is to save the entity into the database but I keep getting this exception:

org.hibernate.HibernateException: save is not valid without active transaction

At first I was getting this exception:

org.hibernate.HibernateException: No CurrentSessionContext configured!

Then I found that I need to add this into my hibernate configuration:

<property name="hibernate.current_session_context_class">thread</property>

This solved this issue but now the above one appears. I am saving entity into database like this:

public void create(T entity) {
    getSessionFactory().getCurrentSession().save(entity);
}

My hibernate.cfg.xml file looks like this:

<hibernate-configuration>
    <session-factory>
        <property name="hibernate.dialect">org.hibernate.dialect.MySQLDialect</property>
        <property name="hibernate.connection.driver_class">com.mysql.jdbc.Driver</property>
        <property name="hibernate.connection.url">jdbc:mysql://localhost:3306/online_tests_management</property>
        <property name="hibernate.connection.username">root</property>
        <property name="hibernate.connection.password">root</property>
        <property name="hibernate.show_sql">true</property>
        <property name="hibernate.hbm2ddl.auto">update</property>
        <property name="hibernate.current_session_context_class">thread</property>

        <mapping class="com.groupgti.onlinetests.management.db.Service"/>
    </session-factory>
</hibernate-configuration>

I am using:

Hibernate-4.1.4.Final
JDK 1.6
Tomcat 6
JSF 2.0
PrimeFaces 3.3.1
MySql

Does someone know where might be the problem?

回答1:

You have to call session.beginTransaction()

public void create(T entity) {
   Session session=getSessionFactory().getCurrentSession();
   Transaction trans=session.beginTransaction();
   session.save(entity);
   trans.commit();
}

回答2:

Try changing your method to be as follows:

public void create(T entity) {
    getSessionFactory().getCurrentSession().beginTransaction();
    getSessionFactory().getCurrentSession().save(entity);
    getSessionFactory().getCurrentSession().endTransaction();
}

Should solve your problem.

回答3:

Do it like this:

  public void create(T entity) {
       org.hibernate.Session ss= getSessionFactory().getCurrentSession();
       Transaction tx=ss.beginTransaction();
       ss.save(entity);
       tx.commit();    
  }

Do the exception handling part yourself.

回答4:

I think you'll find something like this is more robust and appropriate:

Session session = factory.openSession();
Transaction tx = null;
try {
   tx = session.beginTransaction();

   // Do some work like:
   //session.load(...);
   //session.persist(...);
   //session.save(...);

   tx.commit(); // Flush happens automatically
}
catch (RuntimeException e) {
   tx.rollback();
   throw e; // or display error message
}
finally {
    session.close();
}

You cannot "close" the transaction, you can close the session, as you can see. Read this here, it might be useful for you.

来源：https://stackoverflow.com/questions/12002737/org-hibernate-hibernateexception-save-is-not-valid-without-active-transaction

标签

java

mysql

hibernate

persistence