问题
This is a question similar to How to remove undefined and null values from an object using lodash?. However, the solutions proposed there do not conserve the constructor. In addition to that, I want to only delete those keys which starts, say with '_'.
Here is what I am looking for, and can't seem to manage to get from lodash :
Input : new Cons({key1 : 'value1', key2 : {key21 : 'value21', _key22: undefined}, key3: undefined, _key4 : undefined})
Output :
{key1 : 'value1', key2 : {key21 : 'value21'}, key3: undefined}
where for example function Cons(obj){_.extend(this, obj)}
I have a solution with omitBy using lodash, however, I loose the constructor information (i.e. I cannot use instanceof Cons anymore to discriminate the object constructor). forIn looked like a good candidate for the recursive traversal but it only provides me with the value and the key. I also need the path in order to delete the object (with unset).
Please note that:
- the object is any valid javascript object
- the constructor is any javascript valid constructor, and the object comes with the constructor already set.
- the resulting object must have
instanceof whatevertheconstructorwasstill true
Is there a better solution (with lodash or else)?
回答1:
You can create a function that recursively omits keys through the use of omitBy() and mapValues() as an assisting function for traversing keys recursively. Also note that this also supports array traversal for objects with nested arrays or top level arrays with nested objects.
function omitByRecursively(value, iteratee) {
var cb = v => omitByRecursively(v, iteratee);
return _.isObject(value)
? _.isArray(value)
? _.map(value, cb)
: _(value).omitBy(iteratee).mapValues(cb).value()
: value;
}
function Cons(obj) {
_.extend(this, omitByRecursively(obj, (v, k) => k[0] === '_'));
}
Example:
function omitByRecursively(value, iteratee) {
var cb = v => omitByRecursively(v, iteratee);
return _.isObject(value)
? _.isArray(value)
? _.map(value, cb)
: _(value).omitBy(iteratee).mapValues(cb).value()
: value;
}
function Cons(obj) {
_.extend(this, omitByRecursively(obj, (v, k) => k[0] === '_'));
}
var result = new Cons({
key1 : 'value1',
key2 : {
key21 : 'value21',
_key22: undefined
},
key3: undefined,
_key4 : undefined,
key5: [
{
_key: 'value xx',
key7: 'value zz',
_key8: 'value aa'
}
]
});
console.log(result);
.as-console-wrapper{min-height:100%;top:0}
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.12.0/lodash.js"></script>
Update
You can mutate the object itself by creating a function that recursively traverses the object with each() and settles the removal by unset().
function omitByRecursivelyInPlace(value, iteratee) {
_.each(value, (v, k) => {
if(iteratee(v, k)) {
_.unset(value, k);
} else if(_.isObject(v)) {
omitByRecursivelyInPlace(v, iteratee);
}
});
return value;
}
function Cons(obj){_.extend(this, obj)}
var result = omitByRecursivelyInPlace(instance, (v, k) => k[0] === '_');
function omitByRecursivelyInPlace(value, iteratee) {
_.each(value, (v, k) => {
if(iteratee(v, k)) {
_.unset(value, k);
} else if(_.isObject(v)) {
omitByRecursivelyInPlace(v, iteratee);
}
});
return value;
}
function Cons(obj){_.extend(this, obj)}
var instance = new Cons({
key1 : 'value1',
key2 : {
key21 : 'value21',
_key22: undefined
},
key3: undefined,
_key4 : undefined,
key5: [
{
_key: 'value xx',
key7: 'value zz',
_key8: 'value aa'
}
]
});
var result = omitByRecursivelyInPlace(instance, (v, k) => k[0] === '_');
console.log(result instanceof Cons);
console.log(result);
.as-console-wrapper{min-height:100%;top:0}
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.12.0/lodash.js"></script>
回答2:
Disclaimer: I have no idea what lodash supports as built-in functions, but this is very easy to implement with vanilla javascript.
Start with a generic function for filtering your object's keys
// filter obj using function f
// this works just like Array.prototype.filter, except on objects
// f receives (value, key, obj) for each object key
// if f returns true, the key:value appears in the result
// if f returns false, the key:value is skipped
const filterObject = f=> obj=>
Object.keys(obj).reduce((res,k)=>
f(obj[k], k, obj) ? Object.assign(res, {[k]: obj[k]}) : res
, {});
Then a function that filters based on your specific behavior
// filter out keys starting with `_` that have null or undefined values
const filterBadKeys = filterObject((v,k)=> /^[^_]/.test(k) || v !== null && v !== undefined);
Then call it on an object
filterBadKeys({a: null, _b: null, _c: undefined, z: 1});
//=> { a: null, z: 1 }
This can be easily integrated into your constructor now
function Cons(obj) {
_.extend(this, filterBadKeys(obj));
// ...
}
EDIT:
On second thought, instead of butchering a perfectly good function with implicit deep recursion, you could abstract out the generic operations and define a specific "deep" filtering function
const reduceObject = f=> init=> obj=>
Object.keys(obj).reduce((res,k)=> f(res, obj[k], k, obj), init);
// shallow filter
const filterObject = f=>
reduceObject ((res, v, k, obj)=> f(v, k, obj) ? Object.assign(res, {[k]: v}) : res) ({});
// deep filter
const deepFilterObject = f=>
reduceObject ((res, v, k, obj)=> {
if (f(v, k, obj))
if (v && v.constructor === Object)
return Object.assign(res, {[k]: deepFilterObject (f) (v)});
else
return Object.assign(res, {[k]: v});
else
return res;
}) ({});
const filterBadKeys = deepFilterObject((v,k)=> /^[^_]/.test(k) || v !== null && v !== undefined);
filterBadKeys({a: null, _b: null, _c: undefined, _d: { e: 1, _f: null }, z: 2});
//=> { a: null, _d: { e: 1 }, z: 2 }
Integration into your constructor stays the same
function Cons(obj) {
_.extend(this, filterBadKeys(obj));
// ...
}
回答3:
You can use the rundef package.
By default, it will replace all top-level properties with values set to undefined. However it supports the following options:
mutate- set this tofalseto return the same object that you have provided; this will ensure the constructor is not changedrecursive- set this totrueto recursively process your object
Therefore, for your use case, you can run:
rundef(object, false, true)
回答4:
You can use JSON.stringify(), JSON.parse(), RegExp.prototype.test()
JSON.parse(JSON.stringify(obj, function(a, b) {
if (!/^_/.test(a) && b === undefined) {
return null
}
return /^_/.test(a) && !b ? void 0 : b
}).replace(/null/g, '"undefined"'));
var obj = {key1 : 'value1', key2 : {key21 : 'value21', _key22: undefined}, key3: undefined, _key4 : undefined}
var res = JSON.stringify(obj, function(a, b) {
if (!/^_/.test(a) && b === undefined) {
return null
}
return /^_/.test(a) && !b ? void 0 : b
}).replace(/null/g, '"undefined"');
document.querySelector("pre").textContent = res;
res = JSON.parse(res);
console.log(res)
<pre></pre>
来源:https://stackoverflow.com/questions/37246775/how-to-delete-recursively-undefined-properties-from-an-object-while-keeping-th