How do I truncate a list in C#?

问题

I know in python you can do something like myList[1:20] but is there anything similar in C#?

回答1:

var itemsOneThroughTwenty = myList.Take(20);
var itemsFiveThroughTwenty = myList.Skip(5).Take(15);

回答2:

You can use List<T>.GetRange():

var subList = myList.GetRange(0, 20);

From MSDN:

Creates a shallow copy of a range of elements in the source List<T>.

public List<T> GetRange(int index, int count)

回答3:

This might be helpful for efficiency, if you really want to truncate the list, not make a copy. While the python example makes a copy, the original question really was about truncating the list.

Given a List<> object "list" and you want the 1st through 20th elements

list.RemoveRange( 20, list.Count-20 );

This does it in place. This is still O(n) as the references to each object must be removed, but should be a little faster than any other method.

回答4:

sans LINQ quicky...

    while (myList.Count>countIWant) 
       myList.RemoveAt(myList.Count-1);

回答5:

    public static IEnumerable<TSource> MaxOf<TSource>(this IEnumerable<TSource> source, int maxItems)
    {
        var enumerator = source.GetEnumerator();            
        for (int count = 0; count <= maxItems && enumerator.MoveNext(); count++)
        {
            yield return enumerator.Current;
        }
    }

来源：https://stackoverflow.com/questions/3428242/how-do-i-truncate-a-list-in-c