copy a directory structure with file names without content

问题

I have a huge directory structure of movie files. For analysis of that structure I want to copy the entire directory structure, i.e. folders and files however I don't want to copy all the movie files while I want to keep there file names. Ideally I get zero-byte files with the original movie file name.

I tried to and then rsync to my remote machine which didn't fetch the link files.

Any ideas how to do that w/o writing scripts?

回答1:

You can use find:

find src/ -type d -exec mkdir -p dest/{} \; \
       -o -type f -exec touch dest/{} \;

Find directory (-d) under (src/) and create (mkdir -p) them under dest/ or (-o) find files (-f) and touch them under dest/.

This will result in:

dest/src/<file-structre>

You can user mv creatively to resolve this issue.

---

Other (partial) solution can be achieved with rsync:

rsync -a --filter="-! */" sorce_dir/ target_dir/

The trick here is the --filter=RULE option that excludes (-) everything that is not (!) a directory (*/)

回答2:

On ubuntu you can try:

cp -r --attributes-only <source_dir> <target_dir>

It doesn't copy file data. From manpage of cp

--attributes-only
          don't copy the file data, just the attributes

Note: I'm not sure this option available for other distributions, if anybody can confirm please update the answer.

回答3:

ls > listOfMovie.txt; You will have the list of your films in a .txt file .For multiple directories see the man page.

来源：https://stackoverflow.com/questions/11946465/copy-a-directory-structure-with-file-names-without-content