What is the use of LinkedHashMap.removeEldestEntry?

问题

I am aware the answer to this question is easily available on the internet. I need to know what happens if I choose not to removeEldestEntry. Below is my code:

package collection;

import java.util.*;

public class MyLinkedHashMap {

   private static final int MAX_ENTRIES = 2;

   public static void main(String[] args) {
      LinkedHashMap lhm = new LinkedHashMap(MAX_ENTRIES, 0.75F, false) {

         protected boolean removeEldestEntry(Map.Entry eldest) {
            return false;
         }
      };
      lhm.put(0, "H");
      lhm.put(1, "E");
      lhm.put(2, "L");
      lhm.put(3, "L");
      lhm.put(4, "O");

      System.out.println("" + lhm);

   }
}

Even though I am not allowing the removeEldestEntry my code works fine. So, internally what is happening?

回答1:

removeEldestEntry always gets checked after an element was inserted. For example, if you override the method to always return true, the LinkedHashMap will always be empty, since after every put or putAll insertion, the eldest element will be removed, no matter what. The JavaDoc shows a very sensible example on how to use it:

protected boolean removeEldestEntry(Map.Entry eldest){
    return size() > MAX_SIZE;
}

In an alternative way, you might only want to remove an entry if it is unimportant:

protected boolean removeEldestEntry(Map.Entry eldest){
    if(size() > MAX_ENTRIES){
       if(isImportant(eldest)){
          //Handle an important entry here, like reinserting it to the back of the list
          this.remove(eldest.getKey());
          this.put(eldest.getKey(), eldest.getValue());
          //removeEldestEntry will be called again, now with the next entry
          //so the size should not exceed the MAX_ENTRIES value
          //WARNING: If every element is important, this will loop indefinetly!
       } else {
           return true; //Element is unimportant
       }
    return false; //Size not reached or eldest element was already handled otherwise
}

回答2:

Why can't people just answer the OP's simple question!

If removeEldestEntry returns false then no items will ever be removed from the map and it will essentially behave like a normal Map.

回答3:

Your removeEldestEntry method is identical to the default implementation of LinkedHashMap.removeEldestEntry, so your LinkedHashMap will simply behave like a normal LinkedHashMap with no overridden methods, retaining whatever you values and keys put into it unless and until you explicitly remove them by calling remove, removeAll, clear, etc. The advantage of using LinkedHashMap is that the collection views (keySet(), values(), entrySet()) always return Iterators that traverse the keys and/or values in the order they were added to the Map.

回答4:

Expanding on the answer by DavidNewcomb:

I'm assuming that you are learning how to implement a cache.

The method LinkedHashMap.removeEldestEntry is a method very commonly used in cache data structures, where the size of the cache is limited to a certain threshold. In such cases, the removeEldestEntry method can be set to automatically remove the oldest entry when the size exceeds the threshold (defined by the MAX_ENTRIES attribute) - as in the example provided here.

On the other hand, when you override the removeEldestEntry method this way, you are ensuring that nothing ever happens when the MAX_ENTRIES threshold is exceeded. In other words, the data structure would not behave like a cache, but rather a normal map.

来源：https://stackoverflow.com/questions/20772869/what-is-the-use-of-linkedhashmap-removeeldestentry

标签

java

collections