问题
Looking for resources or algorithm to calculate the following in a navigation app:
If my current GPS position is (0,0) and I'm heading 32 degrees at 15 miles per hour, how can I calculate what my position will be in 10 seconds?
i.e.: GPSCoordinate predictedCoord = GPSCoordinate.FromLatLong(0, 0).AddByMovement(32, 15, TimeSpan.FromSeconds(10));
Edit: Current code based on answer below:
public GPSCoordinate AddMovementMilesPerHour(double heading, double speedMph, TimeSpan duration)
{
double x = speedMph * System.Math.Sin(heading * pi / 180) * duration.TotalSeconds / 3600;
double y = speedMph * System.Math.Cos(heading * pi / 180) * duration.TotalSeconds / 3600;
double newLat = this.Latitude + 180 / pi * y / earthRadius;
double newLong = this.Longitude + 180 / pi / System.Math.Sin(this.Latitude * pi / 180) * x / earthRadius;
return GPSCoordinate.FromLatLong(newLat, newLong);
}
回答1:
Here is the complete parametric answer :
variables :
heading: heading (i.e. backwards angle from azimuth 0°, in degrees)speed: velocity (i.e. norm of the speed vector, in miles/hour)lat0,lon0: initial coordinates in degreesdtime: time interval from the start position, in secondslat,lon: predicted coordinates in degreespi: the pi constant (3.14159...)Rt: Earth radius in miles (6378137.0 meters which makes 3964.037911746 miles)
In an (East, North) local frame, the position after the time interval is :
x = speed * sin(heading*pi/180) * dtime / 3600;
y = speed * cos(heading*pi/180) * dtime / 3600;
(with coordinates in miles)
From there you can compute the new position in the WGS84 frame (i.e. latitude and longitude) :
lat = lat0 + 180 / pi * y / Rt;
lon = lon0 + 180 / pi / sin(lat0*pi/180) * x / Rt;
Edit : corrected the last line : *sin(phi) to /sin(phi)
回答2:
Here are the formulas that you need.
http://www.movable-type.co.uk/scripts/latlong.html
Hope that helps.
Bob
[update] Here are the formulas in JavaScript (copied from source)
var lat2 = Math.asin( Math.sin(lat1)*Math.cos(d/R) + Math.cos(lat1)*Math.sin(d/R)*Math.cos(brng) ); var lon2 = lon1 + Math.atan2(Math.sin(brng)*Math.sin(d/R)*Math.cos(lat1), Math.cos(d/R)-Math.sin(lat1)*Math.sin(lat2));
d=distance traveled=velocity x time R=radius of the earth
来源:https://stackoverflow.com/questions/4909380/gps-gis-calculations-algorithm-to-predict-future-position-based-on-movement-mph