问题
I'm trying to find the best way of working out whether the machine my code is running on is big-endian or little-endian. I have a solution that works (although I haven't tested it on a big-endian machine) but it seems a bit clunky:
import struct
little_endian = (struct.pack('@h', 1) == struct.pack('<h', 1))
This is just comparing a 'native' two-byte pack to a little-endian pack. Is there a prettier way?
回答1:
The answer is in the sys module:
>>> import sys
>>> sys.byteorder
'little'
Of course depending on your machine it may return 'big'. Your method should certainly work too though.
来源:https://stackoverflow.com/questions/1346034/whats-the-most-pythonic-way-of-determining-endianness