问题
I have defined a custom Response format as per the Flask-RESTful documentation as follow.
app = Flask(__name__)
api = restful.Api(app)
@api.representation('application/octet-stream')
def binary(data, code, headers=None):
resp = api.make_response(data, code)
resp.headers.extend(headers or {})
return resp
api.add_resource(Foo, '/foo')
I have the following Resource class.
class Foo(restful.Resource):
def get(self):
return something
def put(self, fname):
return something
I want the get() function to return the application/octet-stream type and the put() function to return the default application/json.
How do I go about doing this? The documentation isn't very clear on this point.
回答1:
What representation is used is determined by the request, the Accept header mime type.
A request of application/octet-stream will be responded to by using your binary function.
If you need a specific response type from an API method, then you'll have to use flask.make_response() to return a 'pre-baked' response object:
def get(self):
response = flask.make_response(something)
response.headers['content-type'] = 'application/octet-stream'
return response
回答2:
Just return Flask response objects in your methods.
A response class allows you to provide custom headers (including the content-type): http://flask.pocoo.org/docs/api/#response-objects
来源:https://stackoverflow.com/questions/20243850/flask-restful-return-custom-response-format