问题
I have an array of objects. I want to find by some field, and then to change it:
var item = {...}
var items = [{id:2}, {id:2}, {id:2}];
var foundItem = items.find(x => x.id == item.id);
foundItem = item;
I want it to change the original object. How? (I dont care if it will be in lodash too)
回答1:
You can use findIndex to find the index in the array of the object and replace it as required:
var item = {...}
var items = [{id:2}, {id:2}, {id:2}];
var foundIndex = items.findIndex(x => x.id == item.id);
items[foundIndex] = item;
This assumes unique IDs. If your IDs are duplicated (as in your example), it's probably better if you use forEach:
items.forEach((element, index) => {
if(element.id === item.id) {
items[index] = item;
}
});
回答2:
My best approach is:
var item = {...}
var items = [{id:2}, {id:2}, {id:2}];
items[items.findIndex(el => el.id === item.id)] = item;
Reference for findIndex
And in case you don't want to replace with new object, but instead to copy the fields of item, you can use Object.assign:
Object.assign(items[items.findIndex(el => el.id === item.id)], item)
as an alternative with .map():
Object.assign(items, items.map(el=> el.id === item.id? item : el))
回答3:
An other approach is to use splice.
The
splice()method changes the contents of an array by removing or replacing existing elements and/or adding new elements in place.
N.B : In case you're working with reactive frameworks, it will update the "view", your array "knowing" you've updated it.
Answer :
var item = {...}
var items = [{id:2}, {id:2}, {id:2}];
let foundIndex = items.findIndex(element => element.id === item.id)
items.splice(foundIndex, 1, item)
And in case you want to only change a value of an item, you can use find function :
// Retrieve item and assign ref to updatedItem
let updatedItem = items.find((element) => { return element.id === item.id })
// Modify object property
updatedItem.aProp = ds.aProp
回答4:
May be use Filter.
const list = [{id:0}, {id:1}, {id:2}];
let listCopy = [...list];
let filteredDataSource = listCopy.filter((item) => {
if (item.id === 1) {
item.id = 12345;
}
return item;
});
console.log(filteredDataSource);
Array [Object { id: 0 }, Object { id: 12345 }, Object { id: 2 }]
回答5:
Given a changed object and an array:
const item = {...}
let items = [{id:2}, {id:3}, {id:4}];
Update the array with the new object by iterating over the array:
items = items.map(x => (x.id === item.id) ? item : x)
回答6:
Whereas most of the existing answers are very well, I would like to include an answer using a traditional for loop, which should also be considered here. The OP requests an answer which is ES5/ES6 compatible, and the traditional for loop applies :)
The problem with using array functions in this scenario, is that they don't mutate objects, but in this case, mutation is a requirement. The performance gain of using a traditional for loop is just a (huge) bonus.
const findThis = 2;
const items = [{id:1, ...}, {id:2, ...}, {id:3, ...}];
for (let i = 0, l = items.length; i < l; ++i) {
if (items[i].id === findThis) {
items[i].iAmChanged = true;
break;
}
}
Although I am a great fan of array functions, don't let them be the only tool in your toolbox. If the purpose is mutating the array, they are not the best fit.
回答7:
worked for me
let returnPayments = [ ...this.payments ];
returnPayments[this.payments.findIndex(x => x.id == this.payment.id)] = this.payment;
来源:https://stackoverflow.com/questions/35206125/javascript-es6-es5-find-in-array-and-change