Java - Skip first line while using try with resources

问题

I need to skip the very first line of what is found in the file. My code:

List<String> readStuff() {
    String pathName = "D:/java/eclipse/someStuff.txt";
    List<String> list = new ArrayList<>();
    try (Stream<String> lines = Files.lines(Paths.get(pathName))) {
        list = lines.collect(Collectors.toList());
    } catch (IOException e) {
        System.out.println("Failed to load file.");
    }
    return list;
}

回答1:

You can just invoke skip(n) to skip the first n-th element from the stream. In this case, using skip(1) would skip the first line.

try (Stream<String> lines = Files.lines(Paths.get(pathName))) {
    return lines.skip(1).collect(Collectors.toList());
}

来源：https://stackoverflow.com/questions/38817615/java-skip-first-line-while-using-try-with-resources