问题
I'm trying to make a python program with numpy, but I ran into a problem:
width, height, pngData, metaData = png.Reader(file).asDirect()
planeCount = metaData['planes']
print('Bildgroesse: ' + str(width) + 'x' + str(height) + ' Pixel')
image_2d = np.vstack(list(map(np.uint8, pngData)))
imageOriginal_3d = np.reshape(image_2d, (width, height, planeCount))
imageEdited_3d = imageOriginal_3d
This is my code, to read in a png-Image. Now I want to edit imageEdited_3d but NOT imageOriginal_3d, like this:
imageEdited_3d[x,y,0] = 255
But then the imareOriginal_3d variable has the same values as the imageEdited_3d one...
Does anyone know, how I can fix this? So it doesn't only creates a reference, but it creates a real copy? :/
回答1:
You need to create the copy of the object. You may do it using numpy.copy() since you are having numpy object. Hence, your initialisation should be like:
imageEdited_3d = imageOriginal_3d.copy()
Also there is copy module for creating the deep copy OR, shallow copy. This works independent of object type. For example, your code using copy should be as:
from copy import copy, deepcopy
# Creates shallow copy of object
imageEdited_3d = copy(imageOriginal_3d)
# Creates deep copy of object
imageEdited_3d = deepcopy(imageOriginal_3d)
Description:
A shallow copy constructs a new compound object and then (to the extent possible) inserts references into it to the objects found in the original.
A deep copy constructs a new compound object and then, recursively, inserts copies into it of the objects found in the original.
来源：https://stackoverflow.com/questions/40196995/python-numpy-create-copy-and-not-reference