how to grab the relative path of a file with php

问题

i am trying to catch the relative path to a file to create a share link. From my httpdocs folder on the webserver, my file is here:

jack/single/uploads/folder1/image.jpg

The var $dir . '/' . $file gives me this output:

uploads/folder1/image.jpg

realpath($dir . '/' . $file gives me this output:

/home/vhosts/example.com/subdomains/develop3/httpdocs/jack/single/uploads/folder1/image.jpg

What i want to achieve is this output:

`http://develop3.example.com/jack/single/uploads/folder1/image.jpg`

How can i achieve this, so that i can create a share link?

回答1:

You could use preg_replace on the output of realpath to replace everything up to httpdocs with your site's URL:

echo preg_replace('#^' . preg_quote($_SERVER['DOCUMENT_ROOT']) . '[\\\\/]#', "{$_SERVER['HTTP_HOST']}/", realpath('test6.php')) . "\n";

回答2:

You can use $_SERVER['HTTP_HOST'] to get you site's name:

function get_link($to_file){
    return "https://".$_SERVER['HTTP_HOST']."/jack/single/".$to_file;
}

echo get_link($dir . '/' . $file);

Change the function's url parts according to your project (do you use https or http? Will /jack/single always be the parent folder of uploads?)

来源：https://stackoverflow.com/questions/54550922/how-to-grab-the-relative-path-of-a-file-with-php