1. 技术文章
  2. Save multiple image into mysql php from android but only one image get inserted

Save multiple image into mysql php from android but only one image get inserted

由 北城以北 提交于 2019-12-20 06:27:00

问题


I have three list view in Activity A as below

When the submit button is clicked, the text and image path will be saved into MySQL and the image will be stored in PhotoUpload folder.

I'm able to stored 3 text into MySQL but the problem is only one path of the image is saved into MySQL . Between, the image suppose to save inside PhotoUpload but it just save outside the folder !

It totally frustrating !

Activity A 

  public void uploadImageAndText(ArrayList<ImageAndText> listItems, final String id) { // Assume id holds value 2 (ts_id)
            JSONArray jsonArray = new JSONArray();
            try {
                for (ImageAndText i : listItems) {
                    JSONObject object = new JSONObject();
                    String type = i.getType();
                    String[] Type = type.split(":");
                    object.put("type", Type[1]);
                    Toast.makeText(getApplicationContext(), Type[1], Toast.LENGTH_LONG).show();
                    String amount = i.getAmount();
                    String[] Amount = amount.split(":");
                    object.put("amount", Amount[1]);
                    String description = i.getDescription();
                    String[] Description = description.split(":");
                    object.put("description", Description[1]);
                    Uri uploadImage = i.getImage();
                    Log.e("Image",uploadImage+"");
                    object.put("image", uploadImage.toString());
                    object.put("ts_id", id);
                    jsonArray.put(object);
                }
            } catch (JSONException e) {
                e.printStackTrace();
            }

            AddStaff ru = new AddStaff(jsonArray);
            ru.execute();

        }

        class AddStaff extends AsyncTask<String, Void, String> {
            ProgressDialog loading;

            JSONArray jsonArray;

            AddStaff(JSONArray jsonArray) {
                this.jsonArray = jsonArray;
            }

            @Override
            protected void onPreExecute() {
                super.onPreExecute();
                loading = ProgressDialog.show(AddClaims.this, "Please Wait", null, true, true);
            }

            @Override
            protected String doInBackground(String... params) {

                for (int index = 0; index < jsonArray.length(); index++) {
                    try {
                        JSONObject jsonObject = jsonArray.getJSONObject(index);
                        String strUri = jsonObject.getString("image");
                        HashMap<String, String> data = new HashMap<String, String>();
                        data.put("listItems", jsonArray.toString());
                        data.put(Configs.KEY_IMAGE, getStringImage(Uri.parse(strUri)));
                        Log.e("AAA",jsonArray.toString());
                        Log.e("String",getStringImage(Uri.parse(strUri)));
                        RequestHandler rh = new RequestHandler();
                        String result = rh.sendPostRequest(Configs.STAFF_BENEFIT, data);
                        return result;
                    } catch (Exception e) {
                    }
                }
                return "";
            }

            @Override
            protected void onPostExecute(String s) {
                super.onPostExecute(s);
                loading.dismiss();
                Toast.makeText(getApplicationContext(), s, Toast.LENGTH_LONG).show();
            }
        }


        public String getStringImage(Uri imgUri) {

            try {
                Bitmap bitmap = MediaStore.Images.Media.getBitmap(getContentResolver(), imgUri);
                ByteArrayOutputStream baos = new ByteArrayOutputStream();
                bitmap.compress(Bitmap.CompressFormat.JPEG, 100, baos);
                byte[] imageBytes = baos.toByteArray();
                String encodedImage = Base64.encodeToString(imageBytes, Base64.DEFAULT);
                return encodedImage;
            } catch (Exception e) {
            }

            return "";
        }
    }

staffBenefit.php

<?php
    if( $_SERVER['REQUEST_METHOD']=='POST' ){

        if( !empty( $_POST['listItems'] ) ){

            $mysqli = new mysqli("127.0.0.1:3307", "root", "", "androiddb");
            if( $mysqli->connect_errno ) echo "Failed to connect to MySQL";

            $image = $_POST['image'];

            $listItems = json_decode( $_POST['listItems'], true ); 

            $sql="SELECT id FROM staff_benefit ORDER BY id ASC";

            $id=1;

            $res=$mysqli->query( $sql );
            while( $rs=$res->fetch_object() ) $id=$rs->id;

            $path=time()."$id.png";
            $actualpath="http://192.168.107.115:80/Android/CRUD/PhotoUpload/$path";

            $sql="INSERT INTO `staff_benefit` ( `type`, `amount`, `description`, `image`, `ts_id` ) VALUES ( ?, ?, ?, ?, ? )";
            $stmt=$mysqli->prepare( $sql );

            $pathelements=array( realpath( $_SERVER['DOCUMENT_ROOT'] ), 'CRUD', 'PhotoUpload', '' );
            $savepath = realpath( implode( DIRECTORY_SEPARATOR, $pathelements ) ) . "{$id}.png";

            $bytes=file_put_contents( $savepath, base64_decode( $image ) );
            if( !$bytes ){
                echo 'Error saving image';  
            }

            if ( $stmt && $bytes) {
                 foreach( $listItems as $item ){ 

                    $stmt->bind_param('sssss', $item['type'], $item['amount'], $item['description'], $actualpath, $item['ts_id'] );
                    $res=$stmt->execute();
                    if( !$res ) echo 'Query failed with code: '.$stmt->errno;
                } 
            }
            $mysqli->close();
        }
    }
?>

Output

I check the image path and three of them are the same ! And only one image(2.png) saved, and it is outside the PhotoUpload, not inside :(

path problem ? java problem ? or php problem ???

Edited(php)

<?php
    if( $_SERVER['REQUEST_METHOD']=='POST' ){

        if( !empty( $_POST['listItems'] ) ){

            $mysqli = new mysqli("127.0.0.1:3307", "root", "", "androiddb");
            if( $mysqli->connect_errno ) echo "Failed to connect to MySQL";


            $listItems = json_decode( $_POST['listItems'], true ); 

            $sql="SELECT id FROM staff_benefit ORDER BY id ASC";

            $id=1;

            $res=$mysqli->query( $sql );
            while( $rs=$res->fetch_object() ) $id=$rs->id;



            $sql="INSERT INTO `staff_benefit` ( `type`, `amount`, `description`, `image`, `ts_id` ) VALUES ( ?, ?, ?, ?, ? )";
            $stmt=$mysqli->prepare( $sql );

            $pathelements=array( realpath( $_SERVER['DOCUMENT_ROOT'] ), 'CRUD', 'UploadPhoto', '' );
            $savepath = realpath( implode( DIRECTORY_SEPARATOR, $pathelements ) ) . "{$id}.png";

            foreach( $listItems as $item ){ 
            $path=time()."$id.png";
            $actualpath="http://192.168.107.115:80/Android/CRUD/PhotoUpload/$path";
            $bytes=file_put_contents( $savepath, base64_decode( $item['image'] ) );
            if( !$bytes ){
            echo 'Error saving image';  
             }else{
             $stmt->bind_param('sssss', 
            $item['type'], 
            $item['amount'], 
            $item['description'], 
            $actualpath, 
            $item['ts_id'] );
           $res=$stmt->execute();
        if( !$res ) echo 'Query failed with code: '.$stmt->errno;
    }
} 
            }
            $mysqli->close();
        }

?>

Path

C:\xampp\htdocs\Android\CRUD\UploadPhoto

回答1:


First of all you are overwriting the image data in you doInBackground loop.

Second the PHP upload code is not in the loop

JAVA

You should have only one loop, when you build your JSON, put everything you need there

for (ImageAndText i : listItems) {
    JSONObject object = new JSONObject();

    String type = i.getType();
    String[] Type = type.split(":");
    String amount = i.getAmount();
    String[] Amount = amount.split(":");
    String description = i.getDescription();
    String[] Description = description.split(":");

    //Image
    String image = i.getImage().toString()
    Uri imageUri = Uri.parse(image);

    object.put("amount", Amount[1]);
    object.put("type", Type[1]);
    object.put("description", Description[1]);
    object.put("ts_id", id);
    object.put("image", image);
    object.put(Configs.KEY_IMAGE, getStringImage(imageUri));

    jsonArray.put(object);
}

Then put the JSON in your hashmap to send

@Override
protected String doInBackground(String... params) {
    try {
        HashMap<String, String> data = new HashMap<String, String>();
        data.put("listItems", jsonArray.toString());

        RequestHandler rh = new RequestHandler();
        String result = rh.sendPostRequest(Configs.STAFF_BENEFIT, data);
        return result;
    } catch (Exception e) {
        return "";
    }
}

PHP

The php would change, you won't need $image = $_POST['image'];

You will get the image data from the json $listItems = json_decode( $_POST['listItems'], true );

You would put the upload code in the loop , and insert only on successful upload

foreach( $listItems as $item ){ 
    $path=time()."$id.png";
    $actualpath="http://192.168.107.115:80/Android/CRUD/PhotoUpload/$path";
    $bytes=file_put_contents( $savepath, base64_decode( $item['image'] ) );
    if( !$bytes ){
        echo 'Error saving image';  
    }else{
        $stmt->bind_param('sssss', 
        $item['type'], 
        $item['amount'], 
        $item['description'], 
        $actualpath, 
        $item['ts_id'] );
        $res=$stmt->execute();
        if( !$res ) echo 'Query failed with code: '.$stmt->errno;
    }
}

EDIT:

Full PHP script

<?php
    if( $_SERVER['REQUEST_METHOD']=='POST' ){
        if( !empty( $_POST['listItems'] ) ){
            $listItems = json_decode( $_POST['listItems'], true ); 
            $mysqli = new mysqli("127.0.0.1:3307", "root", "", "androiddb");
            if( $mysqli->connect_errno ) echo "Failed to connect to MySQL";
            $sql="INSERT INTO `staff_benefit` 
                 ( `type`, `amount`, `description`, `image`, `ts_id` ) 
                  VALUES ( ?, ?, ?, ?, ? )";
            if($stmt=$mysqli->prepare($sql )){
                $url="http://192.168.107.115:80/Android/CRUD/PhotoUpload/";
                foreach( $listItems as $item ){ 
                    $image_name = time().".png";
                    $save_path = 'PhotoUpload/'.$image_name;
                    $image_url = $url.$image_name;
                    $bytes=file_put_contents($save_path, base64_decode($item['image']));
                    if( !$bytes ){
                        echo 'Error saving image';  
                    }else{
                        $stmt->bind_param('sssss', 
                        $item['type'], 
                        $item['amount'], 
                        $item['description'], 
                        $image_url, 
                        $item['ts_id'] );
                        if( !$res=$stmt->execute()){ 
                            echo 'Query failed with code: '.$stmt->errno;
                        }
                    }
                } 
            }
            $mysqli->close();
        }
    }
?>


来源：https://stackoverflow.com/questions/34785971/save-multiple-image-into-mysql-php-from-android-but-only-one-image-get-inserted

标签
php
android
mysql
image
android-listview
易学教程内所有资源均来自网络或用户发布的内容，如有违反法律规定的内容欢迎反馈！
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!