jpql order by subquery produces unexpected AST node exception

问题

I translated a working (postgre)sql query to jpql, but hibernate throws a

org.hibernate.hql.ast.QuerySyntaxException: unexpected AST node exception

These are my core model classes:

@Entity
public class Piece {
    @Id
    @GeneratedValue
    public Long id;

    @ManyToOne
    public AUser user;
    public long index;
...
}

@Entity
public class Vote {
    @Id
    @GeneratedValue
    public Long id;

    @ManyToOne
    public AUser receiver;
...
}

@Entity
public class AUser {
    @Id
    @GeneratedValue
    public Long id;

    @OneToMany(mappedBy="receiver", cascade=CascadeType.ALL)
    public List<Vote> receivedVotes;
...
}

Here is my jpql query:

String query = "select p from Piece p order by (select count(v.receiver) from Vote v where v.receiver.id=p.user.id) desc, p.index";

Can anyone explain the exception, why it happens and how to change the query to avoid it. Thanks!

回答1:

JPQL doesn't support subqueries in order by. If I correctly understand your query, you can try something like this:

select p 
from Piece p left join p.user.receivedVotes rv
group by p
order by count(rv) desc, p.index

来源：https://stackoverflow.com/questions/5551459/jpql-order-by-subquery-produces-unexpected-ast-node-exception