Regex in Notepad++ : How to get last part of URLs?

问题

I have some URL like this:

http://www.mywebsite.com/at/hello-everybody-mn0000000003
http://www.mywebsite.com/am/I-dont-care-mw0000322930
http://www.mywebsite.com/ccc/mood/I-love-you-d5207

How to get the last part which removed the last word?

hello-everybody
I-dont-care
I-love-you

回答1:

You could use the below lookahead based regex.

[^\/]+?(?=-[^-\/]+$)

DEMO

回答2:

hope it can help you!

$str = 'http://www.mywebsite.com/at/hello-everybody-mn0000000003';
$str = preg_replace('@http://www.mywebsite.com/(.*)/@','',$str);
$str = substr($str,0,strrpos($str,'-'));

回答3:

Unfortunately, this is the furthest I can get you:

(?!\/)(?:.(?!\/))+(?=-)

This is what it would match:

http://www.mywebsite.com/at/hello-everybody-mn0000000003   Matches: hello-everybody
http://www.mywebsite.com/am/I-dont-care-mw0000322930       Matches: I-dont-care
http://www.mywebsite.com/ccc/mood/I-love-you-d5207         Matches: I-love-you

回答4:

Try this RegEx: /[\w-]+(?=-)/.

Example: https://regex101.com/r/gX3sD2/1

来源：https://stackoverflow.com/questions/27595856/regex-in-notepad-how-to-get-last-part-of-urls