问题
To be clear, let introduse some model:
interface A {
boolean isSomeCase();
}
class AAdapter implements JsonSerializer<A> {
public JsonElement serialize(A src, Type typeOfSrc, JsonSerializationContext context) {
if (src.isSomeCase()) {
/* some logic */
return result;
} else {
JsonObject json = new JsonObject();
JsonElement valueJson = <???>; // TODO serialize src like POJO
json.add(src.getClass().getSimpleName(), valueJson);
return json;
}
}
}
Gson gson = new GsonBuilder()
.registerTypeHierarchyAdapter(A.class. new AAdapter())
.create();
How it is possible to serealize some instance of A, which isSomeCase() = false, like any other object, that is serialized by ReflectiveTypeAdapterFactory.Adapter.
回答1:
You can write a custom TypeAdapterFactory and handle incoming object's isSomeCase() result in its TypeAdapter's write() method and apply your logic there:
public class ATypeAdapterFactory implements TypeAdapterFactory {
public TypeAdapter<A> create(Gson gson, TypeToken type) {
if (!A.class.isAssignableFrom(type.getRawType())) {
// Check if incoming raw type is an instance of A interface
return null;
}
final TypeAdapter<A> delegate = gson.getDelegateAdapter(this, type);
return new TypeAdapter<A>() {
@Override
public void write(JsonWriter out, A value) throws IOException {
if(value.isSomeCase()) {
// your custom logic here
out.beginObject();
out.name("x").value(0);
out.endObject();
} else {
// default serialization here
delegate.write(out, value);
}
}
@Override
public A read(JsonReader in) throws IOException {
return delegate.read(in);
}
};
}
}
Test:
final GsonBuilder gsonBuilder = new GsonBuilder();
// Register custom type adapter factory
gsonBuilder.registerTypeAdapterFactory(new ATypeAdapterFactory());
final Gson gson = gsonBuilder.create();
A aSomeCaseTrue = new AImpl(true);
System.out.print("aSomeCaseTrue:" + gson.toJson(aSomeCaseTrue));
// writes; aSomeCaseTrue:{"x":0}
A aSomeCaseFalse = new AImpl(false);
System.out.print("aSomeCaseFalse:" + gson.toJson(aSomeCaseFalse););
// writes; aSomeCaseFalse:{"someCase":false}
Extras:
1) Your interface:
interface A {
boolean isSomeCase();
}
2) A sample class which implements your sample interface:
class AImpl implements A {
boolean someCase;
public AImpl(boolean value) {
this.someCase = value;
}
@Override
public boolean isSomeCase() {
return someCase;
}
}
来源:https://stackoverflow.com/questions/26592904/gson-serialize-deserialize-object-of-class-that-have-registered-type-hierarchy