How to explode a string by any integer? Regex?

问题

This seems like it must be so simple, but regular expressions are extremely confusing to me. I am grabbing $_GET variables that will look like typeX, optionX, groupX, etc. where X equals any positive whole integer. I need to then split the string at the integer so that type1 becomes an array of "type and "1", however type10 must become an array of "type and "10" not "type" and "1" and "0".

I am wholly unfamiliar with regex patterns but ended up coming up with:

$array = preg_split("#\\d+#", $key, -1, PREG_SPLIT_NO_EMPTY);
print_r($array);

but it just removed the number from the end rather than split the string into two arrays as was shown by the result:

Array ( [0] => type )

Also, I am unsure as if this would further split the number ten into a one and a zero, which I don't want. I feel like this is probably a mind numbingly simple solution but I am spinning in circles here.

回答1:

You should use the PREG_SPLIT_DELIM_CAPTURE flag to capture the group which you made the split on. Here's an example:

<?php

$key= "group12";
$pattern = "/(\d+)/";

$array = preg_split($pattern, $key, -1, PREG_SPLIT_NO_EMPTY | PREG_SPLIT_DELIM_CAPTURE);
print_r($array);

?>

Note that you combine several flags using the | "bitwise or" operator.

Output:

Array
(
    [0] => group
    [1] => 12
)

回答2:

Try this one:

/(\D+)(\d+)/

PHP example code:

<?php
$str = 'test189';
$pattern = '/(\D+)(\d+)/';

$res = preg_match_all($pattern, $str, $matches);
var_dump($matches);

?>

回答3:

Use preg_match with capturing parentheses:

<?php

$str = "type10";

$matches = array();

preg_match('/([a-zA-Z]+)(\d+)/', $str, $matches );

print_r($matches);

?>

Outputs:

Array(
    0 => "type10"
    1 => "type"
    2 => "10"
)

Then, to get rid of the first element:

<?php
array_shift($matches);
print_r($matches);
?>

To give:

Array(
    0 => "type"
    1 => "10"
)

来源：https://stackoverflow.com/questions/7908327/how-to-explode-a-string-by-any-integer-regex

标签

php

regex

preg-split