$q.reject and handling errors in AngularJS chained promises

问题

I'm having trouble understanding a basic concept of error handling with chaining promises. In order to learn the rules, I have written a simple example, guessing what the result will be. But unfortunatly it doesn't behave as I though it will. I have read multiple articles about the subject but perhaps can't I get details because of my poor english language.

Anyway, here is my code :

    var promiseStart = $q.when("start");
    var promise1 = promiseStart.then(function() {
            return Serviceforpromise1.get();
    });
    var promise2 = promise1.then(function(data1)
    {
            return Serviceforpromise2.get(data1);
    },function(error)
    {
            return $q.reject();
    });
    var promiseend = promise2.then(function(data2)
    {
            return data2;
    },function(error)
    {
            return error;
    });
    return promiseend;

Well I know that it can be way better coded but it's just for the purpose. Here is the code of Serviceforpromise1 function :

    function Serviceforpromise1()
    {
            ...
            return $http.get(*whatever*).then(function (data){
                return data;
            },function(error)
            {
                return $q.reject();
            });
    }

Consider only the case of Serviceforpromise1's failure. A $q.reject is sent back to main chain so I'm waiting the error callback of "promise1 .then(" to be called and it worked as expected. I decided for the example to transfert the error to the "promise2 .then" so in this error callback I added the line return $q.reject(); But it never reached the second error callback (the "promise2 .then" one) and I don't understand why (like Serviceforpromise1, I returned a rejected promise !)

I will be happy to deeply understand what is happening here. Thanks for your help.

回答1:

Your understanding is correct, and the problem appears to lie somewhere in the way you are trying to observe this behavior (in something you haven't shown us).

If you return a rejected promise from either a success or error handler in then(), then the promise returned by then() will resolve to a rejected promise. Observe:

angular.module('app', [])
    .controller('C', [
    '$q',

function ($q) {
    var promiseStart = $q.when("start");
    var promise1 = promiseStart.then(function (value) {
        console.log('Got a value:', value);
        return $q.reject('Error!');
    });

    var promise2 = promise1.then(function (data1) {
        return "Got some stuff";
    }, function (error) {
        console.log("Caught an error:", error);
        return $q.reject('New error');
    });

    var promiseend = promise2.then(function (data2) {
        return data2;
    }, function (error) {
        console.log('Caught an error:', error);  // <-- this is logged to the console
        return error;
    });

    return promiseend;
}]);

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.10/angular.min.js"></script>
<div ng-app='app' ng-controller='C'></div>

One thing to note here is that in that last handler, you are returning the error variable, and not throwing an exception or returning a rejected promise. So in this case, promiseend will successfully resolve with the value of that error variable.

来源：https://stackoverflow.com/questions/29175455/q-reject-and-handling-errors-in-angularjs-chained-promises

标签

javascript

angularjs

promise

chaining