How can I combine 4 bytes into a 32 bit unsigned integer?

问题

I'm trying to convert 4 bytes into a 32 bit unsigned integer.

I thought maybe something like:

UInt32 combined = (UInt32)((map[i] << 32) | (map[i+1] << 24) | (map[i+2] << 16) | (map[i+3] << 8));

But this doesn't seem to be working. What am I missing?

回答1:

Your shifts are all off by 8. Shift by 24, 16, 8, and 0.

回答2:

Use the BitConverter class.

Specifically, this overload.

回答3:

BitConverter.ToInt32()

You can always do something like this:

public static unsafe int ToInt32(byte[] value, int startIndex)
{
    fixed (byte* numRef = &(value[startIndex]))
    {
        if ((startIndex % 4) == 0)
        {
            return *(((int*)numRef));
        }
        if (IsLittleEndian)
        {
            return (((numRef[0] | (numRef[1] << 8)) | (numRef[2] << 0x10)) | (numRef[3] << 0x18));
        }
        return ((((numRef[0] << 0x18) | (numRef[1] << 0x10)) | (numRef[2] << 8)) | numRef[3]);
    }
}

But this would be reinventing the wheel, as this is actually how BitConverter.ToInt32() is implemented.

来源：https://stackoverflow.com/questions/6406324/how-can-i-combine-4-bytes-into-a-32-bit-unsigned-integer